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love history [14]
4 years ago
14

Simplify the expression

Mathematics
1 answer:
yaroslaw [1]4 years ago
8 0
\bf ~~~~~~~~~~~~\textit{negative exponents}
\\\\
a^{-n} \implies \cfrac{1}{a^n}
\qquad \qquad
\cfrac{1}{a^n}\implies a^{-n}
\qquad \qquad 
a^n\implies \cfrac{1}{a^{-n}}
\\\\
-------------------------------\\\\
5^{-2}\div 5^4\implies \cfrac{5^{-2}}{5^4}\implies \cfrac{1}{5^25^4}\implies \cfrac{1}{5^{2+4}}\implies \cfrac{1}{5^6}\implies \cfrac{1}{15625}
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When 5 is added to a certain number and the result is multiplied by 3 the final answer is 27 what is the original number
Katyanochek1 [597]

Answer:

The original number is 4

Step-by-step explanation:

Let x be the number.

5 is added to x => 5+x

When it is multiplied by 3,

3*(5+x) = 27

=> 15 + 3x = 27

Subtract 15,

3x = 27 - 15 = 12

Divide by 3,

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3 0
3 years ago
Read 2 more answers
WRITE AN EQUATION TO DESCRIBE THE RELATIONSHIP BETWEEN J AND Mj | 4 | 12 | 20m | 3 | 9 | 15
galina1969 [7]

First, we can use the points (4,3) and (20,15) to find the slope of the line:

\begin{gathered} s=\frac{m_2─m_1}{j_2─j_1}=\frac{15─3}{20─4}=\frac{12}{16}=\frac{3}{4} \\ s=\frac{3}{4} \end{gathered}

Now we can find the relation function using the point (4,3) and the slope s=3/4

\begin{gathered} m─m_1=s(j─j_1) \\ \Rightarrow m─3=\frac{3}{4}(j─4)=\frac{3}{4}j─(\frac{12}{4})=\frac{3}{4}j─3 \\ m=\frac{3}{4}j \end{gathered}

therefore, the equation to describe the relationship between J and M is m=3/4j

4 0
1 year ago
How I solve 2x-1=10?<br> Thx
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Answer:

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Step-by-step explanation:

2x-1=10

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2x=11

divide by 2 on each side

x=5.5

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4 years ago
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Answer:

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I hope this helps!

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