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jeka94
3 years ago
14

What is the solution of this question. 9988 ÷ 23 =

Mathematics
1 answer:
gizmo_the_mogwai [7]3 years ago
4 0

Answer:

434\frac{6}{23}  

I hope this helps!

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Is it possible to make an eight-pointed star out of quilt pieces with two angles of 130?
Lena [83]

Answer:

yes

Step-by-step explanation:

yessssssssss

3 0
3 years ago
Probability The average time between incoming calls at a switchboard is 3 minutes.if a call has just come in,the probability tha
Stels [109]

Answer:

a) 0.1535

b) 0.4866

c) 0.8111

Step-by-step explanation:

The probability that the next call come within the next t minutes is:

  • p(t) = 1 -e ^{- t/3}

According to this model,

a) the probability that a call in comes within 1/2 minutes is p(t) = 1 -e ^{- (1/2)/3} =0.1535

b) the probability that a call in comes within 2 minutes is  p(t) = 1 -e ^{-2/3} =0.4866

c) the probability that a call in comes within 5 minutes is  p(t) = 1 -e ^{-5/3} =0.8111

6 0
3 years ago
​f(x)
padilas [110]
nshsu1273 Rowe 2827
5 0
3 years ago
I need help with this homework can anyone help me. I need work too, help is appreciated:)
quester [9]
Let x = # of tickets sold in advance 
Let y = # of tickets sold the day of 


Cost of the tickets & total sales: 6x & 10y = 6828

You also know y = x + 206

Take the equation mentioned above y = x + 206 and sub it in anywhere the variable y is in the other equations so you'll have this:
6x + 10(x+206) = 6828

Now solve for x to get x = 298

To finish the problem, you must now find the number of y tickets sold.
Sub your x value that you found back into the equation y = x + 206 and you'll get y = 504.

So, 298 tickets were sold in advance and 504 tickets were sold the day of
3 0
3 years ago
Read 2 more answers
The area of a rectangle is 56 cm. the length is 2 less than x and the width is 5 less than twice of x. solve for x
Nostrana [21]

Answer:

x=\frac{9+\sqrt{449}}{4}

Step-by-step explanation:

The area of a rectangle is:

A=l\cdot w

First let's write both the length and the width in terms of x:

l=x-2

<u>How we obtained the answer</u>:

The question states the length is "2 less than x". In this case, "less" is a keyword that represents subtraction. Therefore, "2 less than x" is "x-2".

w=2x-5

<u>How we obtained the answer</u>:

The question states the width is "5 less than twice of x". First, start by figuring out what "twice of x" is. The keyword is "twice" which represents multiplication. Therefore, "twice of x" can be written as "2x". Then, using the same keyword from before ("less"), "5 less than..." represents "2x-5".

Given:

Area = 56 cm

l=x-2

w=2x-5

Find:

x

A=l\cdot w

56=(x-2)(2x-5)

FOIL (Firsts, outsides, insides, lasts):

56=2x^2-4x-5x+10\\56=2x^2-9x+10

Subtract 10 from both sides:

46=2x^2-9x

Subtract 46 from both sides (forms a quadratic equation):

0=2x^2-9x-46

Use the quadratic formula:

{x = \frac{{ - b \pm \sqrt {b^2 - 4ac} }}{{2a}}}  where 0=ax^2+bx+c

Therefore:

x=\frac{9\pm\sqrt{81-4(2)(-46)}}{2(2)}\\x=\frac{9\pm\sqrt{81+368}}{4}\\\\x=\frac{9\pm\sqrt{449}}{4}

The answer is:

x=\frac{9+\sqrt{449}}{4}

This is because if we used subtraction, we would get a negative value, and we cannot have a negative length/width.

4 0
2 years ago
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