1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
maksim [4K]
3 years ago
12

Can someone please help me I really need this answer!!!!

Mathematics
2 answers:
Tom [10]3 years ago
4 0
The answer is A.90 but I’m not sure
VLD [36.1K]3 years ago
4 0
The formula to use is 
z = (x+y)/2
where
x and y are the measures of the minor arcs (highlighted in blue) and z is the measure of the intersecting chord angles

In this case,
x = measure of minor arc DE = 30
y = measure of minor arc AC = unknown
z = measure of angle ABC = 90

So,
z = (x+y)/2
90 = (30+y)/2
2*90 = 30+y
180 = 30+y
y+30 = 180
y = 180-30
y = 150

Answer: C) 150 degrees
You might be interested in
HELP I NEED HELP ASAP
Vilka [71]

Answer:

x-intercept(s):  

( − 3 + √ 17 /4 , 0 ) , ( − 3 − √ 17 /4 , 0 )

y-intercept(s):  ( 0 , 1 )

Vertex= ( − 3 /4 , 17/ 8 )

Increasing on:  ( − ∞ , − 3 /4 )

Decreasing on:  ( − 3/ 4 , ∞ )

Its negative

Step-by-step explanation:

6 0
3 years ago
A2 = [1 2 3; 4 5 6; 7 8 9; 3 2 4; 6 5 4; 9 8 7]
34kurt

Answer:

Remember, a basis for the row space of a matrix A is the set of rows different of zero of the echelon form of A.

We need to find the echelon form of the matrix augmented matrix of the system A2x=b2

B=\left[\begin{array}{cccc}1&2&3&1\\4&5&6&1\\7&8&9&1\\3&2&4&1\\6&5&4&1\\9&8&7&1\end{array}\right]

We apply row operations:

1.

  • To row 2 we subtract row 1, 4 times.
  • To row 3 we subtract row 1, 7 times.
  • To row 4 we subtract row 1, 3 times.
  • To row 5 we subtract row 1, 6 times.
  • To row 6 we subtract row 1, 9 times.

We obtain the matrix

\left[\begin{array}{cccc}1&2&3&1\\0&-3&-6&-3\\0&-6&-12&-6\\0&-4&-5&-2\\0&-7&-14&-5\\0&-10&-20&-8\end{array}\right]

2.

  • We subtract row two twice to row three of the previous matrix.
  • we subtract 4/3 from row two to row 4.
  • we subtract 7/3 from row two to row 5.
  • we subtract 10/3 from row two to row 6.

We obtain the matrix

\left[\begin{array}{cccc}1&2&3&1\\0&-3&-6&-3\\0&0&0&0\\0&0&3&2\\0&0&0&2\\0&0&0&2\end{array}\right]

3.

we exchange rows three and four of the previous matrix and obtain the echelon form of the augmented matrix.

\left[\begin{array}{cccc}1&2&3&1\\0&-3&-6&-3\\0&0&3&2\\0&0&0&0\\0&0&0&2\\0&0&0&2\end{array}\right]

Since the only nonzero rows of the augmented matrix of the coefficient matrix are the first three, then the set

\{\left[\begin{array}{c}1\\2\\3\end{array}\right],\left[\begin{array}{c}0\\-3\\-6\end{array}\right],\left[\begin{array}{c}0\\0\\3\end{array}\right] \}

is a basis for Row (A2)

Now, observe that the last two rows of the echelon form of the augmented matrix have the last coordinate different of zero. Then, the system is inconsistent. This means that the system has no solutions.

4 0
3 years ago
M^5-m^7. probably easier for most but having a brain fart<br><br>​
Dennis_Churaev [7]

\bf m^5-m^7\implies \begin{array}{llll} m^5&(1-m^2)\\\\ &(1^2-m^2)\\\\ &(1-m)(1+m) \end{array} \\\\[-0.35em] ~\dotfill\\\\ ~\hfill m^5(1-m)(1+m)~\hfill

recall that

1² = 1

1⁴ = 1

1⁸⁹⁹⁹⁹⁹⁹⁹⁹ = 1

8 0
3 years ago
Hi! I would like some help with this problem please? It would be grateful
iragen [17]

Answer:

16

Step-by-step explanation:

Since the ratio is constant, you can do divisions here.

4/3 = 4/3

6/8 = 4/3

Etc.

From here, you take 12, and multiple it by 4/3, and get 16.

4 0
3 years ago
Read 2 more answers
PLEASE HELP ME!!!
IgorC [24]

Answer:

Option A)   Inside the circle

Step-by-step explanation:

step 1

Find the radius of the circle

we know that

The radius is equal to the distance from the center to any point on the circle

the formula to calculate the distance between two points is equal to

d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}

we have

A(-5,-8),M(-1,-3)

substitute the values

r=\sqrt{(-3+8)^{2}+(-1+5)^{2}}

r=\sqrt{(5)^{2}+(4)^{2}}

r=\sqrt{41}\ units

step 2

Find the distance from the center to point V

we know that

If the distance from the center to point V is equal to the radius, then the point V lie on the circle

If the distance from the center to point V is less than the radius, then the point V lie inside the circle

If the distance from the center to point V is greater than the radius, then the point V lie outside the circle

we have

A(-5,-8),V(-11,-6)

substitute in the formula

d=\sqrt{(-6+8)^{2}+(-11+5)^{2}}

d=\sqrt{(2)^{2}+(-6)^{2}}

d=\sqrt{40}\ units

so

\sqrt{40}\ units< \sqrt{41}\ units

The distance from the center to point V is less than the radius

therefore

The point V lie inside the circle

4 0
4 years ago
Other questions:
  • Find the annual percentage rate, using the annual percentage rate table.
    8·1 answer
  • Which postulate can be used to prove that the two triangles below are Congruent?
    13·2 answers
  • Help pleaseeeeeeeeeee
    15·1 answer
  • The sum of three numbers is 108. The second number is four times greater than the first number, and the third number is 18 more
    12·1 answer
  • For f(x)=3x+5 and g(x)=3/4x+5 determine if each statement is true or false. A. f(x) and g(x) have the same y intercept. B. f(x)
    15·1 answer
  • Select the correct answer.
    7·1 answer
  • Two standard number cubes are tossed.
    6·2 answers
  • What is the area of the hexagon below? only real answers
    14·2 answers
  • Please help me I need the answer for this question. correct one please
    10·1 answer
  • A right triangle has one angle that measures 44°. What is the measure of the other acute angle?
    15·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!