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Neporo4naja [7]
3 years ago
6

4x+2y=10 X-y=13 Write in (x,y)

Mathematics
1 answer:
Bad White [126]3 years ago
5 0

Answer:

(x = 6, y = -7)

Step-by-step explanation:

Solve the following system:

{4 x + 2 y = 10 | (equation 1)

x - y = 13 | (equation 2)

Subtract 1/4 × (equation 1) from equation 2:

{4 x + 2 y = 10 | (equation 1)

0 x - (3 y)/2 = 21/2 | (equation 2)

Divide equation 1 by 2:

{2 x + y = 5 | (equation 1)

0 x - (3 y)/2 = 21/2 | (equation 2)

Multiply equation 2 by 2/3:

{2 x + y = 5 | (equation 1)

0 x - y = 7 | (equation 2)

Multiply equation 2 by -1:

{2 x + y = 5 | (equation 1)

0 x+y = -7 | (equation 2)

Subtract equation 2 from equation 1:

{2 x+0 y = 12 | (equation 1)

0 x+y = -7 | (equation 2)

Divide equation 1 by 2:

{x+0 y = 6 | (equation 1)

0 x+y = -7 | (equation 2)

Collect results:

Answer:  {x = 6 , y = -7

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Alenkinab [10]

well the absolute means positive so it would be a positive 1.6


6 0
3 years ago
Read 2 more answers
HELPPPP!!!
Hatshy [7]

Answer:

(x - 1)²/4² - (y - 2)²/2² = 1 ⇒ The bold labels are the choices

Step-by-step explanation:

* Lets explain how to solve this problem

- The equation of the hyperbola is x² - 4y² - 2x + 16y - 31 = 0

- The standard form of the equation of hyperbola is

  (x - h)²/a² - (y - k)²/b² = 1 where a > b

- So lets collect x in a bracket and make it a completing square and

  also collect y in a bracket and make it a completing square

∵ x² - 4y² - 2x + 16y - 31 = 0

∴ (x² - 2x) + (-4y² + 16y) - 31 = 0

- Take from the second bracket -4 as a common factor

∴ (x² - 2x) + -4(y² - 4y) - 31 = 0

∴ (x² - 2x) - 4(y² - 4y) - 31 = 0

- Lets make (x² - 2x) completing square

∵ √x² = x

∴ The 1st term in the bracket is x

∵ 2x ÷ 2 = x

∴ The product of the 1st term and the 2nd term is x

∵ The 1st term is x

∴ the second term = x ÷ x = 1

∴ The bracket is (x - 1)²

∵  (x - 1)² = (x² - 2x + 1)

∴ To complete the square add 1 to the bracket and subtract 1 out

   the bracket to keep the equation as it

∴ (x² - 2x + 1) - 1

- We will do the same withe bracket of y

- Lets make 4(y² - 4y) completing square

∵ √y² = y

∴ The 1st term in the bracket is x

∵ 4y ÷ 2 = 2y

∴ The product of the 1st term and the 2nd term is 2y

∵ The 1st term is y

∴ the second term = 2y ÷ y = 2

∴ The bracket is 4(y - 2)²

∵ 4(y - 2)² = 4(y² - 4y + 4)

∴ To complete the square add 4 to the bracket and subtract 4 out

   the bracket to keep the equation as it

∴ 4[y² - 4y + 4) - 4]

- Lets put the equation after making the completing square

∴ (x - 1)² - 1 - 4[(y - 2)² - 4] - 31 = 0 ⇒ simplify

∴ (x - 1)² - 1 - 4(y - 2)² + 16 - 31 = 0 ⇒ add the numerical terms

∴ (x - 1)² - 4(y - 2)² - 16 = 0 ⇒ add 14 to both sides

∴ (x - 1)² - 4(y - 2)² = 16 ⇒ divide both sides by 16

∴ (x - 1)²/16 - (y - 2)²/4 = 1

∵ 16 = (4)² and 4 = (2)²

∴ The standard form of the equation of the hyperbola is

   (x - 1)²/4² - (y - 2)²/2² = 1

4 0
3 years ago
Please help me ASAP!!
vodomira [7]

It's A.



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4 0
3 years ago
1,2,4,7,11,16,22, ___,____<br> What is the rule?
Paha777 [63]
Find rates of change until you find a constant.

dy/dx=1,2,3,4,5,6

d2y/dx2=1,1,1,1,1  

So the acceleration, d2y/d2x, is constant.  This means that this is a quadratic sequence of the form a(n)=an^2+bn+c.  So we can set up a system of equations to solve for the values of a,b, and c.  Using the first three points, (1,1), (2,2), and (3,4) we have:

9a+3b+c=4, 4a+2b+c=2, and a+b+c=1  getting the differences...

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2a=1, so a=1/2 making 5a+b=2 become:

2.5+b=2, so b=-1/2, making a+b+c=1 become:

1/2-1/2+c=1, so c=1  so the rule is:

a(n)=0.5x^2-0.5x+1  or if you prefer to not have decimals

a(n)=(x^2-x+2)/2
6 0
3 years ago
Read 2 more answers
Can anyone help me?.
4vir4ik [10]
The third one is the correct answer
7 0
2 years ago
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