What's the unit rate of 2.50 for 5 onces

Which is another way to select (5-x)

amid [387]

5+x because it is order of operation

3 0

3 years ago

Solve the following system of equations by the substitution method.

ruslelena [56]

5x = y + 6 (I)
2x - 3y = 4 (II)
-------------------
We have:
5x = y + 6 → $x = \frac{y+6}{5}$

Soon:
2x - 3y = 4 → $2* (\frac{y+6}{5}) - 3y = 4\to \frac{2y+12}{5} - 3y = 4$
<span>least common multiple (5)
</span> $\frac{2y+12}{5} - 3y = 4\to \frac{2y+12}{\diagup\!\!\!\!\!5} - \frac{15y}{\diagup\!\!\!\!\!5} = \frac{20}{\diagup\!\!\!\!\!5}$
$2y + 12 - 15y = 20$
$- 15y + 2y = 20 - 12$
$- 13y = 8$
$\boxed{\boxed{y = - \frac{8}{13} }}\end{array}}\qquad\quad\checkmark$

4 0

3 years ago

What is the most precise name for a quadrilateral with the following vertices:

lozanna [386]

Answer:

The most precise name for a quadrilateral ABCD is a parallelogram

Step-by-step explanation:

we have

A(2,3) B(7,2) C(6,-1) D(1,0)

Plot the quadrilateral'

using a graphing tool

The quadrilateral ABCD in the attached figure

Verify the length of the sides

the formula to calculate the distance between two points is equal to

$d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}$

step 1

Find distance AB

A(2,3) B(7,2)

substitute

$d=\sqrt{(2-3)^{2}+(7-2)^{2}}$

$d=\sqrt{(-1)^{2}+(5)^{2}}$

$d_A_B=\sqrt{26}\ units$

step 2

Find distance BC

B(7,2) C(6,-1)

substitute

$d=\sqrt{(-1-2)^{2}+(6-7)^{2}}$

$d=\sqrt{(-3)^{2}+(-1)^{2}}$

$d_B_C=\sqrt{10}\ units$

step 3

Find distance CD

C(6,-1) D(1,0)

substitute

$d=\sqrt{(0+1)^{2}+(1-6)^{2}}$

$d=\sqrt{(1)^{2}+(-5)^{2}}$

$d_C_D=\sqrt{26}\ units$

step 4

Find distance AD

A(2,3) D(1,0)

substitute

$d=\sqrt{(0-3)^{2}+(1-2)^{2}}$

$d=\sqrt{(-3)^{2}+(-1)^{2}}$

$d_A_D=\sqrt{10}\ units$

step 5

Compare the length sides

AB=CD

BC=AD

Opposite sides are congruent

<em>Verify the slope of the sides</em>

The formula to calculate the slope between two points is equal to

$m=\frac{y2-y1}{x2-x1}$

step 1

Find slope AB

A(2,3) B(7,2)

substitute

$m=\frac{2-3}{7-2}$

$m=\frac{-1}{5}$

$m_A_B=-\frac{1}{5}$

step 2

Find slope BC

B(7,2) C(6,-1)

substitute

$m=\frac{-1-2}{6-7}$

$m=\frac{-3}{-1}$

$m_B_C=3$

step 3

Find slope CD

C(6,-1) D(1,0)

substitute

$m=\frac{0+1}{1-6}$

$m=\frac{1}{-5}$

$m_C_D=-\frac{1}{5}$

step 4

Find slope AD

A(2,3) D(1,0)

substitute

$m=\frac{0-3}{1-2}$

$m=\frac{-3}{-1}$

$m_A_D=3$

step 5

Compare the slopes

$m_A_B=m_C_D$

$m_B_C=m_A_D$

The slope of the opposite sides are equal, that means, opposite sides are parallel

The slopes of consecutive sides are not opposite reciprocal, that means, consecutive sides are not perpendicular

therefore

The most precise name for a quadrilateral ABCD is a parallelogram

8 0

3 years ago

If 5 bags cost $255.35 how much would 2 bags cost

VARVARA [1.3K]

The answer would be $102.14 if you divide 255.35 by 5 then multiply it by 2, you'll get 102.14
255.35 divided by 5 = 51.07 x 2 = 102.14

Hope this helps! ;)

3 0

3 years ago

Read 2 more answers

Can somebody plz help answer these three word questions correctly thanks a lot >33

miss Akunina [59]

Answer:

a) The percent of their games the hockey team won is 60%

b) The percent of their games the hockey team lost is 37% to the nearest percent

c) The percent of their games the hockey team tied is 3% to the nearest percent

Step-by-step explanation:

In any game, there are 3 situations

Win
Tie
Lose

The sum of the three situations is the total number of playing that game

∵ The hockey team won 72 out of 120 games and tied 4

∴ The number of winning games = 72

∴ The number of tying games = 4

∴ The number of total games = 120

→ Find the number of losing games

∵ Win + ty + lose = total games

∴ 72 + 4 + lose = 120

∴ 76 + lose = 120

→ Subtract 76 from both sides

∴ lose = 44

∴ The number of losing games = 44

Now let answer the questions

a)

∵ P%(win) = (winning ÷ total) × 100%

∴ P%(win) = (72 ÷ 120) × 100%

∴ P%(win) = 60%

The percent of their games the hockey team won is 60%

b)

∵ P%(lose) = (losing ÷ total) × 100%

∴ P%(lose) = (44 ÷ 120) × 100%

∴ P%(lose) = 36.66667% = 37% to the nearest percent

The percent of their games the hockey team lost is 37% to the nearest percent

c)

∵ P%(tie) = (tying ÷ total) × 100%

∴ P%(tie) = (4 ÷ 120) × 100%

∴ P%(tie) = 3.333333% = 3% to the nearest percent

The percent of their games the hockey team tied is 3% to the nearest percent

6 0

2 years ago