3 3/5 x (-8 1/3) = <br> A. -30<br> B. 4 3/5<br> C. 8 4/5<br> D. -24

15 points to answer this question

Mamont248 [21]

it is none since there is no relation

4 0

3 years ago

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I need help please!!

Alex73 [517]

Answer:

Sorry I could only find the answer to the second part.

y=56x

6 0

3 years ago

Help ASAP! Please explain!

Dmitrij [34]

All real numbers greater than or equal to -8. You can see 3 is a minimum point because at 3 the numbers start to increase again. -8 is the lowest number and the function is increasing as x approaches infinity starting at 3.

6 0

3 years ago

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There are six balls in the bag. Two are basketballs, three are playground balls, and one is a soccer ball. What is the probabili

aleksandr82 [10.1K]

Answer:

$\frac{1}{6}=0.16$

Step-by-step explanation:

Given : There are six balls in bag

Basketballs=2

Playground balls =3

Soccer ball =1

To Find : the probability that if you pick one of the balls without looking, it will be a soccer ball

Solution :

Total no. of balls = 6

No. of soccer balls = 1

Probability = favorable outcomes / total outcomes

Since total outcomes = total no. of balls =6

And favorable outcome = no. of soccer balls = 1

Thus , Probability of getting soccer ball = $\frac{1}{6}$

Hence the probability that if you pick one of the balls without looking, it will be a soccer ball:

$\frac{1}{6}=0.16$

7 0

3 years ago

(12x + y + z = 26

mel-nik [20]

Option D. D has the matrix of constants [[12], [11], [4]].

Step-by-step explanation:

Step 1:

With the given equations, we can form matrices to represent them.

The coefficients of x, y, and z form a matrix of order 3 ×3, the variables x, y, and z form a matrix of order 1 ×3 and the constants form a matrix of order 1 ×3.

Step 2:

The linear system A is represented as

$\left[\begin{array}{ccc}12&1&1\\1&-11&0\\1&-1&4\end{array}\right]$ $\left[\begin{array}{ccc}x\\y\\z\end{array}\right]$ $= \left[\begin{array}{ccc}26\\17\\23\end{array}\right]$ .

Step 3:

The linear system B is represented as

$\left[\begin{array}{ccc}4&1&1\\1&-11&0\\1&-1&12\end{array}\right]$ $\left[\begin{array}{ccc}x\\y\\z\end{array}\right]$ $= \left[\begin{array}{ccc}23\\17\\26\end{array}\right]$ .

Step 4:

The linear system C is represented as

$\left[\begin{array}{ccc}1&1&1\\1&-1&0\\1&-1&1\end{array}\right]$ $\left[\begin{array}{ccc}x\\y\\z\end{array}\right]$ $= \left[\begin{array}{ccc}4\\11\\12\end{array}\right]$ .

Step 5:

The linear system D is represented as

$\left[\begin{array}{ccc}1&1&1\\1&-1&0\\1&-1&1\end{array}\right]$ $\left[\begin{array}{ccc}x\\y\\z\end{array}\right]$ $= \left[\begin{array}{ccc}12\\11\\4\end{array}\right]$ .

Step 6:

Of the four options, the linear system D has the matrix of constants [[12], [11], [4]]. So the answer is option D. D.

4 0

3 years ago

3 3/5 x (-8 1/3) = A. -30 B. 4 3/5 C. 8 4/5 D. -24