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scZoUnD [109]
3 years ago
12

The demand function for a type of portable radio is given by the model d=85−6x2, where d is measured in dollars and x is measure

d in millions of units. The production cost is $25.00 per radio. Given that profit = revenue - costs answer the following parts. (Hint: Revenue is demand times number sold. Costs are productions costs per number sold.)
Part A: Write an equation giving profit as a function of x million radios sold. Part B: The company currently produces 3 million radios and makes a profit of $18,000,000, but would like to scale back production. What lesser number of radios could the company produce to yield the same profit?
Part C: Give a graph for the profit and label the parts of the graph.

Mathematics
1 answer:
Lostsunrise [7]3 years ago
3 0

Answer:

Part A : The required Profit equation : \text{Profit}= 60x-6x^3

Part B : 0.303 million radios the profit became 18 million.

Part C : The graph is attached below.

Step-by-step explanation:

Given : The demand function for a type of portable radio is given by the model d=85-6x^2, where d is measured in dollars and x is measured in millions of units. The production cost is $25.00 per radio.  

Note: Given that profit = revenue - costs

Revenue is demand times number sold.

Costs are productions costs per number sold.

To find :

Part A: Write an equation giving profit as a function of x million radios sold.

Solution : Let x be the number of radios.

Revenue is demand times number sold

\text{Revenue}= x\times (85-6x^2)

\text{Revenue}= 85x-6x^3

Let the cost of x number of radios is 25x.            

Profit = Revenue - Costs

\text{Profit}= 85x-6x^3-25x

P(x)= 60x-6x^3

The required Profit equation : P(x)= 60x-6x^3

 

Part B : The company currently produces 3 million radios and makes a profit of $18,000,000, but would like to scale back production. What lesser number of radios could the company produce to yield the same profit?

Solution :  It is shown graphically which is attached in part c

When we scale back production we get that,

When we sold 0.303 million radios the profit became 18 million.

Part C : Give a graph for the profit and label the parts of the graph.

The graph is attached below which shows the profitable radios points.

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6 0
3 years ago
In a batch of 100 parts, 40 are red, 50 are L-shaped and 22 are both red and L-shaped. What is probability that a part picked fr
Bogdan [553]

The probability that a part picked from this batch at random is either red or L-shaped is 0.68

Step-by-step explanation:

Let us revise some rules of probability

The addition rules are:

  • P(A or B) = P(A) + P(B) ⇒ mutually exclusive (events cannot happen  at the same time)
  • P(A or B) = P(A) + P(B) - P(A and B) ⇒ non-mutually exclusive (if they  have at least one outcome in common)

∵ A batch has 100 parts

∵ 40 are red

- Probability of an event is the [even occurs/total outcomes]

∴ P(red) = \frac{40}{100}=0.4

∵ 50 are L-shaped

∴ P(L-shaped) = \frac{50}{100}=0.5

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∴ P(red and L-shaped) = \frac{22}{100}=0.22

This is non-mutually exclusive because there is a common between them, so we will use the 2nd rule

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∴ P(red or L-shaped) = 0.4 + 0.5 - 0.22

∴ P(red or L-shaped) = 0.68

The probability that a part picked from this batch at random is either red or L-shaped is 0.68

Learn more:

You can learn more about the probability in brainly.com/question/2254182

#LearnwithBrainly

3 0
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vesna_86 [32]
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Median(b): 13
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The median now divides this data into two halves.

Now we take the medians of the two remaining halves.

Median(Half1): 7.5
Median(Half2): 17

Mark off the minimum and maximum.

Min: 5
Max: 21

Now graph!

Your median(Half1) is incorrect, since your median for the first half is 9. Since our median for the first half is 7.5, the answer would be Answer Choice C.
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