3. Gach Perry is conducting an inventory of the PE equipment at OCS. He counts
1 answer:
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Part 3) <span>Given triangle XYZ as shown at right find YZ rounded to the nearest tenth
we know that
</span><span>the sum of the internal angles of a triangle add up to 180 degrees
</span>so
m∠X=180-[55+29]----> 96°
applying the law of sines
YZ/sin X=35/sin 55°------> YZ=35*sin 96/sin 55-----> YZ=42.49
YZ=42.5 units
the answer Part 3) is
YZ=42.5 units
Part 4)
we know that
OQ/NQ=PR/NR
NQ=4X+(2X+2)---> 6X+2
OQ=2X+2
PR=15
NR=24+15----> 39
(2X+2)/(6X+2)=15/39
39*(2X+2)=15*(6X+2)
78X+78=90X+30
90X-78X=78-30
12X=48
X=4
The answer part 4) is
x=4
Part 5) A trapezoid is show below. Calculate the measure of angle x. Round to the nearest tenth of a degree
see the picture with letters attached to better understand the problem
we know that
BC=36-28-----> 8 ft
sin x=BC/AC-----> sin x=8/12
x=arc sin(8/12)-------> x=41.81°------> x=41.8°
the answer Part 5) is
x=41.8°
we know that
</span><span>the sum of the internal angles of a triangle add up to 180 degrees
</span>so
m∠X=180-[55+29]----> 96°
applying the law of sines
YZ/sin X=35/sin 55°------> YZ=35*sin 96/sin 55-----> YZ=42.49
YZ=42.5 units
the answer Part 3) is
YZ=42.5 units
Part 4)
we know that
OQ/NQ=PR/NR
NQ=4X+(2X+2)---> 6X+2
OQ=2X+2
PR=15
NR=24+15----> 39
(2X+2)/(6X+2)=15/39
39*(2X+2)=15*(6X+2)
78X+78=90X+30
90X-78X=78-30
12X=48
X=4
The answer part 4) is
x=4
Part 5) A trapezoid is show below. Calculate the measure of angle x. Round to the nearest tenth of a degree
see the picture with letters attached to better understand the problem
we know that
BC=36-28-----> 8 ft
sin x=BC/AC-----> sin x=8/12
x=arc sin(8/12)-------> x=41.81°------> x=41.8°
the answer Part 5) is
x=41.8°
Answer:
Option F.
Step-by-step explanation:
we know that
The solution of the inequality of the graph is the shaded area above the solid line
step 1
Find the equation of the solid line
The intercepts are
The y-intercept is the point (0,b)
The x-intercept is the point (-b,0)
Find the slope
The equation of the solid line is
step 2
The solution of the inequality is the shaded area above the solid line
therefore
the inequality is equal to