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Elodia [21]
3 years ago
11

What is the perimeter of the triangle shown on the coordinate plane, to the nearest tenth of a unit?

Mathematics
2 answers:
Alexxx [7]3 years ago
7 0

Answer:the answer is 21.6.


Step-by-step explanation:


Leno4ka [110]3 years ago
3 0
To calculate the perimeter, consider each side separately.

Right side: This is easiest since it's a vertical line - it's 7 units long.

Top side: If you look carefully, this side is really the hypotenuse of a triangle that is 1 unit tall and 6 units long. Using the Pythagorean Theorem, you can calculate the length of the hypotenuse to be 1^2 + 6^2 = c^2 --> c = 6.1

Left side: just like the top side, this side is the hypotenuse of a triangle that is 6 units tall and 6 units long. Pythagoras again: 6^2 + 6^2 = c^2 --> c = 8.5

Add these three numbers to get the perimeter: 7 + 6.1 + 8.5 = 21.6
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Find the volume of the solid bounded by z = 2 - x2 - y2 and z = 1. Express your answer as a decimal rounded to the hundredths pl
butalik [34]

Answer:

The answer is "(\frac{\pi}{2})".

Step-by-step explanation:

z = 2 - x^2 - y^2.........(1) \\\\z = 1.............(2)  

Let add equation 1 and 2:

Using formula: x^2+y^2=1 \\\\

convert to polar coordinates

r=2

\theta \varepsilon (0=\pi)=z\\\\V=\int^{2\pi}_{\theta=0}\int^{1}_{\pi=0}\int^{z_{2}}_{z_1} r \ dr \d \theta\\\\

    =\int^{2\pi}_{0}\int^{1}_{0}  (Z_2-z_1)r  \ dr \d \theta\\\\=\int^{2\pi}_{0}\int^{1}_{0} 1- (-1-x^2-y^2) r \ dr \d \theta\\\\=\int^{2\pi}_{0}\int^{1}_{0} (+1 \pm r^2) r \ dr \d \theta\\\\=\int^{2\pi}_{0}\int^{1}_{0} (-r^3 + r)  \ dr \d \theta\\\\=\int^{2\pi}_{0} (-\frac{r^4}{4}+\frac{r^2}{1})^{1}_{0}  \d \theta\\\\=\int^{2\pi}_{0} (\frac{1}{4})  \d \theta\\\\=(\frac{2 \pi}{4}) \\\\=(\frac{\pi}{2}) \\\\

8 0
3 years ago
Find the slope of the ordered pair. A(4,6) B(5,8)
andrezito [222]

Answer:

<h2>The slope is 2</h2>

Step-by-step explanation:

Step one:

we are required to find the slope of the given data points

A(4,6) B(5,8)

hence the x and y values correspond to

x1=4

y1=6

x2=5

y2=8

Step two:

Required is the slope which is

slope= y2-y1/x2-x1

Slope=8-6/5-4

Slope= 2/1

<em><u>Hence the slope of the ordered pair is 2</u></em>

3 0
3 years ago
There are 14 girls and 2 boys taking karate lessons. Write the ratio that compares the number of girls taking karate lessons to
Delvig [45]

Answer:

The correct answer is 7 : 8.

Step-by-step explanation:

There are 14 girls and 2 boys taking karate lessons.

Total number of students taking the karate class is 16.

The ratio that compares the number of girls taking karate lessons to the total number of students taking karate lessons is given by 14 : 16 = 7 : 8.

This can be interpreted as for every 8 students in the karate lesson, 7 of them are girls.

8 0
3 years ago
BIG POINTS Please solve. Thanks!
Nitella [24]

9^1/3 * 3^x = 27^4/5

Rewrite 9 as 3^2

(3^2)^1/3 * 3^x = 27^4/5

Multiply the exponents in the first term:

3^2/3 * 3^x = 27^4/5

Use power rule to combine exponents:

3^(2/3 +x) = 27^4/5

Rewrite the 2nd term:

3^(2/3 +x) = (3^3)^4/5

Set the exponents only to equal:

2/3 + x = 3(4/5)

Solve for x:

simplify the right side:

2/3 + x = 12/5

Subtract 2/3 from both sides:

x = 26/15

3 0
3 years ago
Find four distinct complex numbers (which are neither purely imaginary nor purely real) such that each has an absolute value of
Luda [366]

Answer:

  • 0.5 + 2.985i
  • 1 + 2.828i
  • 1.5 + 2.598i
  • 2 + 2.236i

Explanation:

Complex numbers have the general form a + bi, where a is the real part and b is the imaginary part.

Since, the numbers are neither purely imaginary nor purely real a ≠ 0 and b ≠ 0.

The absolute value of a complex number is its distance to the origin (0,0), so you use Pythagorean theorem to calculate the absolute value. Calling it |C|, that is:

  • |C| = \sqrt{a^2+b^2}

Then, the work consists in finding pairs (a,b) for which:

  • \sqrt{a^2+b^2}=3

You can do it by setting any arbitrary value less than 3 to a or b and solving for the other:

\sqrt{a^2+b^2}=3\\ \\ a^2+b^2=3^2\\ \\ a^2=9-b^2\\ \\ a=\sqrt{9-b^2}

I will use b =0.5, b = 1, b = 1.5, b = 2

b=0.5;a=\sqrt{9-0.5^2}=2.958\\ \\b=1;a=\sqrt{9-1^2}=2.828\\ \\b=1.5;a=\sqrt{9-1.5^2}=2.598\\ \\b=2;a=\sqrt{9-2^2}=2.236

Then, four distinct complex numbers that have an absolute value of 3 are:

  • 0.5 + 2.985i
  • 1 + 2.828i
  • 1.5 + 2.598i
  • 2 + 2.236i
4 0
3 years ago
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