Answer : The empirical of the compound is,
Solution : Given,
If percentage are given then we are taking total mass is 100 grams.
So, the mass of each element is equal to the percentage given.
Mass of C = 19.36 g
Mass of H = 3.25 g
Mass of O = 77.39 g
Molar mass of C = 12 g/mole
Molar mass of H = 1 g/mole
Molar mass of O = 16 g/mole
Step 1 : convert given masses into moles.
Moles of C =
Moles of H =
Moles of O =
Step 2 : For the mole ratio, divide each value of moles by the smallest number of moles calculated.
For C =
For H =
For o =
The ratio of C : H : O = 1 : 2 : 3
The mole ratio of the element is represented by subscripts in empirical formula.
The Empirical formula =
Therefore, the empirical of the compound is,