Answer : The enthalpy of combustion of ethanol is, -1366.8 KJ/mole
Explanation :
In this problem we assumed that heat given by the hot body is equal to the heat taken by the cold body.
First we have to calculate the heat released by calorimeter.
where,
= heat released by calorimeter = ?
c = heat capacity of bomb calorimeter =
m = mass of ethanol = 1.752 g
= initial temperature of calorimeter = 294.42 K
= final temperature of calorimeter = 295.92 K
Now put all the given values in the above formula, we get
Now we have to calculate the moles of ethanol.
Now we have to calculate the enthalpy of combustion of ethanol.
where,
= enthalpy of combustion = ?
q = heat released = -51.98 KJ
n = number of moles used in combustion = 0.03803 mole
The negative sign indicate the heat released during the reaction.
Therefore, the enthalpy of combustion of ethanol is, -1366.8 KJ/mole