Step1:use the rules for multiplication
-2x(-12)x(-8)
Step2:Multiply
-(2x12x8)
Step3:multiply
-(24x8)
Solution:
-192
The area of a triangle can be calculated as half the product of base length and height. We want the area to be no greater than 10 in².
a) (1/2)(4)(2x-3) ≤ 10
b) 4x -6 ≤ 10 . . . . . simplify
... 4x ≤ 16 . . . . . . . .add 6
... x ≤ 4 . . . . . . . . . divide by the coefficient of x
c) The maximum value of (2x -3) in is (2·4 -3) in = 5 in.
The triangle should be no more than 5 in high to have an area less than 10 in².
A^2+b^2=c^2
A=63
B=?
C=87
63^2+b^2=87^2
3969+b^2=7569
-3969 both sides
B^2=3600
Square root both sides
B=60in
The gaps in the area needs to be closed so the data you use is lenient
Answer:
The equation of the line is y = -7/8x + 11/2
Step-by-step explanation:
Since we have the slope and a point to start, we can use point-slope form to find the equation.
y - y1 = m(x - x1)
Use the slope for m and the point at (x1, y1). Then solve for y.
y - 9 = -7/8(x + 4)
y - 9 = -7/8x - 7/2
y = -7/8x + 11/2
