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2 years ago

Please answer correctly !!!!!!!!!!!!! Will make brainliest answer !!!!!!!!!!!

Mathematics

1 answer:

photoshop1234 [79]2 years ago

7 0

Answer:

down by 1 units

right/left by 4 units

You might be interested in

The sum of a number and its additive inverse is equal to _____.

prohojiy [21]

The sum of a number and its additive inverse is equal to zero. The correct option among all the options that are given in the question is the second option or option "b". If we assume "x" to be a real number, then its additive inverse is "-x". On adding these two, we can see that the result comes to zero.

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3 years ago

Y = 4X-3 4.88-1:2y = 3.6

Rzqust [24]

Answer:

google it , it'll help you

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3 years ago

A store is having a sale in which the cost of any item is 35% off.

vichka [17]

Answer:

1. no

2. yes

3. no

4. yes

Step-by-step explanation:

only the second and last expression works. If x is the final cost, and it is 35% off, then you are subtracting 0.35xor keeping 0.65x

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3 0

3 years ago

Use the information provided to determine a 95% confidence interval for the population variance. A researcher was interested in

Leno4ka [110]

Answer:

The 95% confidence interval for the population variance is (8.80, 32.45).

Step-by-step explanation:

The (1 - α)% confidence interval for the population variance is given as follows:

$\frac{(n-1)\cdot s^{2}}{\chi^{2}_{\alpha/2}}\leq \sigma^{2}\leq \frac{(n-1)\cdot s^{2}}{\chi^{2}_{1-\alpha/2}}$

It is provided that:

n = 20

s = 3.9

Confidence level = 95%

⇒ α = 0.05

Compute the critical values of Chi-square:

$\chi^{2}_{\alpha/2, (n-1)}=\chi^{2}_{0.05/2, (20-1)}=\chi^{2}_{0.025,19}=32.852\\\\\chi^{2}_{1-\alpha/2, (n-1)}=\chi^{2}_{1-0.05/2, (20-1)}=\chi^{2}_{0.975,19}=8.907$

*Use a Chi-square table.

Compute the 95% confidence interval for the population variance as follows:

$\frac{(n-1)\cdot s^{2}}{\chi^{2}_{\alpha/2}}\leq \sigma^{2}\leq \frac{(n-1)\cdot s^{2}}{\chi^{2}_{1-\alpha/2}}$

$\frac{(20-1)\cdot (3.9)^{2}}{32.852}\leq \sigma^{2}\leq \frac{(20-1)\cdot (3.9)^{2}}{8.907}\\\\8.7967\leq \sigma^{2}\leq 32.4453\\\\8.80\leq \sigma^{2}\leq 32.45$

Thus, the 95% confidence interval for the population variance is (8.80, 32.45).

4 0

3 years ago

Luke and isabella make scale drawings.The scale from isabella's drawing is 6 m to 3 cm. The height of the fountain in isabella's

den301095 [7]

Answer:

The answer is " $2.5 \ cm$ "

Step-by-step explanation:

While Luke is 5m to 2cm in size, it implies that every 2cm to Luke's drawing is 5m in real life. That real pond width must therefore be 5 m, given the fountain's width is 2 cm. As shown in the illustration, the step size for IsabelLa from the illustration to real life is $\frac{6}{3} =2$ , which makes it simple to multiply any measure in the cm of her illustration by 2 to accomplish the exact size in m. So, in another direction around, they just have to divide the value by 2, instead of the divide from reality for drawing. So if the actual worth is 5m, it ought to be $\frac{5}{2} = 2.5 \ cm$ in its width.

7 0

2 years ago