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3 years ago

Please help me i dont understand

Mathematics

2 answers:

mr_godi [17]3 years ago

8 0

A = 2.76 x 10^12 = 27600000000
w = 4.6 x 10^5 = 460000
w x l = A
2760000000000/460000 = 6000000
l = 6000000
(w x 2) + (l x 2) = perimeter
((4.6 x 10^5) x 2) + ((6.0 x 10^6) x 2) = 12920000

ANSWER: perimeter = 129.2 x 10^5

maks197457 [2]3 years ago

4 0

The perimeter is 5.52000092 x 10^12
The numbers are in scientific notation.

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Solve the following system of equations:<br><br> x + 3y = −4<br> x + 5y = −6<br><br> pls and thx

Agata [3.3K]

Answer:

x = -1 y = -1

Step-by-step explanation:

x + 3y = −4

x + 5y = −6

Multiply the first equation by -1

-x - 3y = 4

The add to the second equation to eliminate x

-x - 3y = 4

x + 5y = −6

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2y = -2

Divide by 2

2y/2 = -2/2

y = -1

Now solve for x

x+3y = -4

x +3(-1) = -4

x -3 = -4

Add 3 to each side

x-3+3 = -4+3

x = -1

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3 years ago

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victus00 [196]

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4 years ago

If the system given has parallel lines, what is the answer?

uysha [10]

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3 years ago

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2. Given a quadrilateral with vertices (−1, 3), (1, 5), (5, 1), and (3,−1):

zlopas [31]

<h2>Explanation:</h2>

In every rectangle, the two diagonals have the same length. If a quadrilateral's diagonals have the same length, that doesn't mean it has to be a rectangle, but if a parallelogram's diagonals have the same length, then it's definitely a rectangle.

So first of all, let's prove this is a parallelogram. The basic definition of a parallelogram is that it is a quadrilateral where both pairs of opposite sides are parallel.

So let's name the vertices as:

$A(-1,3) \\ \\ B(1,5) \\ \\ C(5,1) \\ \\ D(3,-1)$

First pair of opposite sides:

<u>Slope:</u>

$\text{For AB}: \\ \\ m=\frac{5-3}{1-(-1)}=1 \\ \\ \\ \text{For CD}: \\ \\ m=\frac{1-(-1)}{5-3}=1 \\ \\ \\ \text{So AB and CD are parallel}$

Second pair of opposite sides:

<u>Slope:</u>

$\text{For BC}: \\ \\ m=\frac{1-5}{5-1}=-1 \\ \\ \\ \text{For AD}: \\ \\ m=\frac{-1-3}{3-(-1)}=-1 \\ \\ \\ \text{So BC and AD are parallel}$

So in fact this is a parallelogram. The other thing we need to prove is that the diagonals measure the same. Using distance formula:

$d=\sqrt{(y_{2}-y_{1})^2+(x_{2}-x_{1})^2} \\ \\ \\ Diagonal \ BD: \\ \\ d=\sqrt{(5-(-1))^2+(1-3)^2}=2\sqrt{10} \\ \\ \\ Diagonal \ AC: \\ \\ d=\sqrt{(3-1)^2+(-5-1)^2}=2\sqrt{10} \\ \\ \\$

So the diagonals measure the same, therefore this is a rectangle.

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3 years ago

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