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3 years ago

PLEASE HELP FAST!!!!!! How many triangles can be constructed using the following three side lengths: 4.8 cm, 2.1 cm, and 2.6 cm?

Mathematics

1 answer:

34kurt3 years ago

7 0

Answer:

no triangles

Step-by-step explanation:

why?

the triangle inequality theorem

this theorem states that the sum of any two sides must be bigger than or equal to the third side. however, the sum of 2.1 and 2.6 is less than 4.8

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Which of the following equations have the correct notation? Check all that apply. (Btw, most of my questions are from Apex learn

Llana [10]

The best and most correct answer among the choices provided by the question is the third choice.

The notation "<span>AB (with line over) =4" is the equation that has the most correct notation.</span>
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3 years ago

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Find the equation of the line that is parallel to the line x+3y=-15 that passes through the origin

Monica [59]

You would subtract x from each side. It would then be 3y=-x-15. Then you would divide all of the equation by 3. Your final answer would be y=-3x-5.

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3 years ago

12.3 Write the first five terms of the sequence whose general term is <img src="https://tex.z-dn.net/?f=a_%7Bn%7D%3D3%5E%7Bn%7D%

weeeeeb [17]

Answer:

7,13,31,85,247......

Step-by-step explanation:

$a_n =3^n + 4$

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1 year ago

(x + 1 < -1) ∩ (x + 1 < 1)

stealth61 [152]

Answer: ok that’s confusing

Step-by-step explanation:

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3 years ago

1. A gambler makes 100 column bets at roulette. The chance of winning on any one play is 12/38. The gambler can either win $ 5 o

lapo4ka [179]

Answer:

a) Expected amount of the gambler's win = $0.209

b) SD = 2.26

c)P (X >1) = P(z >0.35) = 0.36317

Step-by-step explanation:

The probability of winning, p = 12/38 =6/19

Probability of losing, q = 1 -p = 1-6/19

q = 13/19

Win amount = $5

Loss amount = $2

a) Expected total amount of win = ((6/19)*5) - ((13/19)*2)

Expected total amount of win = 1.579 - 1.369

Expected amount of win, E(X) = $0.209

b) Standard Deviation for the total amount of the gambler's win

$SD = \sqrt{E(X^{2}) - (E(X))^{2} }$

E(X²) = (6/19)*5² - (13/19)*2²

E(X²) = 5.158

$SD = \sqrt{5.158 - 0.209^2}$

SD = 2.26

c) probability that, in total, the gambler wins at least $1.

P(X >1)

$z = \frac{X - \mu}{\sigma}$

μ = E(x) = 0.209

z = (1-0.209)/2.26

z = 0.35

P( X >1) = P(z >0.35)

P(z >0.35) = 1 - P(z <0.35)

P(z >0.35) = 1 - 0.63683

P(z >0.35) = 0.36317

5 0

3 years ago