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Sonbull [250]
3 years ago
14

A theme park uses positive numbers to represent when a roller coaster is above ground and negative numbers to represent when a r

oller coaster is below ground. How would the theme park represent a roller coaster that is 3 meters below ground?
Mathematics
1 answer:
elixir [45]3 years ago
8 0

Answer:

-3 meters

Step-by-step explanation:

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musickatia [10]

Answer:

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In the second one you are missing a (x -5)which means 9x(x -5) or when you factor it out it will be 9x^2 - 45x

Step-by-step explanation:

3x^2 -23x + 40 = (3x - 8) (x - 5)

3x^2 -17x + 24 = (3x -8) ( x - 3)

7 0
2 years ago
Is anybody better at this then I am ?
lbvjy [14]

Answer:

hmmm

Step-by-step explanation:

8 0
3 years ago
X² - 2x=0<br> what is this...like what’s the outcome
Tanzania [10]

Answer:

x=0  x=2

Step-by-step explanation:

X² - 2x=0

Factor

x(x-2) = 0

Using the zero product property

x=0  x-2 =0

x=0  x=2

4 0
3 years ago
A bin is constructed from sheet metal with a square base and 4 equal rectangular sides. if the bin is constructed from 48 square
kondaur [170]
This is a problem of maxima and minima using derivative.

In the figure shown below we have the representation of this problem, so we know that the base of this bin is square. We also know that there are four square rectangles sides. This bin is a cube, therefore the volume is:

V = length x width x height

That is:

V = xxy = x^{2}y

We also know that the <span>bin is constructed from 48 square feet of sheet metal, s</span>o:

Surface area of the square base = x^{2}

Surface area of the rectangular sides = 4xy

Therefore, the total area of the cube is:

A = 48 ft^{2} =  x^{2} + 4xy

Isolating the variable y in terms of x:

y =  \frac{48- x^{2} }{4x}

Substituting this value in V:

V =  x^{2}( \frac{48- x^{2} }{x}) = 48x- x^{3}

Getting the derivative and finding the maxima. This happens when the derivative is equal to zero:

\frac{dv}{dx} = 48-3x^{2} =0

Solving for x:

x =  \sqrt{\frac{48}{3}} =  \sqrt{16} = 4

Solving for y:

y =  \frac{48- 4^{2} }{(4)(4)} = 2

Then, <span>the dimensions of the largest volume of such a bin is:
</span>
Length = 4 ft
Width =  4 ft
Height = 2 ft

And its volume is:

V = (4^{2} )(2) = 32 ft^{3}

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3 years ago
Write a recursive formula for the following arithmetic sequence 10, 6, 2, -2
shtirl [24]

a(n)=a(n-1)-4

a(1)=10

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3 years ago
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