Givens
h = 10
b = 4x^y + 2xy^2
Formula
Area = 1/2 b * h
Solution
Substitute the givens into the formula
Area = 1/2 * 10 * (4x^2y + 2xy^2)
Area = 5 * (4x^2y + 2xy^2) What to do next? I would remove the brackets
Area = 5 * 4x^2y + 5 * 2xy^2
Area = 20x^2y + 10xy^2 <<<< Answer
Also possible is to take out more common factors.
The common factor of 4x^2y + 2xy^2 is 2xy and what is left over is 2x + y
So you would have Area = 5*2xy(2x + y)
If you have been given answers please list them.
What is the shape for your problem?
Coordinate 1 is : (0,3)
Coordinate 2 is : (-4,-2)
Coordinate 3 is : (-1,-5)
Coordinate 4 is (4,0)
Hope this helps!
Répondre:
r <27
Explication étape par étape:
Compte tenu de l'inégalité 5r + 9> 10r - 126
Nous devons trouver l'ensemble de solutions
5r + 9> 10r - 126
Ajouter 126 des deux côtés
5r + 9 + 126> 10r - 126 + 126
5r + 135> 10r
5r-10r> -135
-5r> -135
Divisez les deux côtés par -5 (notez que le signe changera)
-5r / -6 <-135 / -5
r <27
Par conséquent, les ensembles de solutions sont des valeurs inférieures à 27
I don’t know I hope u get it