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charle [14.2K]
3 years ago
13

Write a quadratic function f whose zeros are -2 and -9

Mathematics
2 answers:
IgorLugansk [536]3 years ago
7 0
Can you restate the question more better to help you ?
olchik [2.2K]3 years ago
6 0

Answer:

f(x) = x^2 + 11x + 18.

Step-by-step explanation:

As the zeroes are -2 and -9 the factored form  is

f(x) = a(x - (-2))(x -  (-9))   where a is some constant.

As we want any quadratic function with theses zeros we  can let a = 1 so:

f(x) = (x + 2)(x + 9)

f(x) = x^2 + 2x + 9x + 18

f(x) = x^2 + 11x + 18.

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Ber [7]
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5 0
3 years ago
Which equation could be used to find the length of the hypotenuse?
suter [353]
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Which piece of additional information can be used to prove △CEA ~ △CDB?
Slav-nsk [51]

<u>Answer-</u>

<em>The correct answer is</em>

<em>∠BDC and ∠AED are right angles</em>

<u>Solution-</u>

In the ΔCEA and ΔCDB,

m\angle BCD=m\angle ACE

As this common to both of the triangle.

If ∠BDC and ∠AED are right angles, then m\angle E=90=m\angle D

Now as

∠BCD = ∠ACE and ∠BDC = ∠AED,

∠DBC and ∠EAC will be same. (as sum of 3 angles in a triangle is 180°)

Then, ΔCEA ≈ ΔCDB

Therefore, additional information can be used to prove ΔCEA ≈ ΔCDB is ∠BDC and ∠AED are right angles.


5 0
3 years ago
Read 2 more answers
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