A) For this problem, we will need to use a normal calculation, in that we find the z-score and the area to the right using Table A.
z = (10 - 7.65) / 1.45
z = 1.62
area to the left for a z-score of 1.62 = 0.9474
area to the right for a z-score of 1.62 = 0.0526
The probability that a randomly selected ornament will cost more than $10 is 0.0526 or 5.26%.
B) For this problem, we will use the binomial probability formula since the problem is asking for the probability that exactly 3 ornaments cost over $10. There are two forms of this equation. One is <em>nCr x p^r x q^n-r</em> and the other is <em>(n r) x p^r x (1 - p)^n-r</em>. I will show both formulas below.
8C3 x 0.0526^3 x 0.9474^5
(8 3) x 0.0526^3 x 0.9474^5
With both equations, the answer is the same. Whichever you are more familiar or comfortable with is the one I would recommend you use.
The probability that exactly 3 of the 8 ornaments cost over $10 is 0.00622 or 0.622%.
Hope this helps!! :)
because when you add 1768 and 978 it would equal $2746 so the total between the both is 2746 so your answer is 2746
Answer:
it equals 39 yd²
Step-by-step
Area= 1/2 base= 18 height= 4 1/3
multiply 1/2 x 18 = 9
9 x 4 1/3= 39
the answer is 39 yd²
So the train is pulling about 50 cars in total, and there's about 30 boxes of freight in each car.
30 x 50 = 1500
The best estimate would be near 1500 boxes of freight through the whole train.
1 GB is 2.857143
You can simplify
