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inysia [295]
4 years ago
9

Four friends are going to split the cost of a pizza. If p stands for the cost of the pizza, which of the following expressions c

ould represent what each friend will pay?
A.4p
B.p - 4
C.p
D.p/4
Mathematics
1 answer:
Natasha2012 [34]4 years ago
5 0

Answer: A

Step-by-step explanation:

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Peytons car used 6 gallons to travel 192 miles how many gallons of gas would she need t I travel 480 miles
ELEN [110]

Answer:

15 gallons

Step-by-step explanation:

if 6gallons = 192 miles

then x gallons 480 miles

x = (6*480)/192

x = 2880/192

x = 15 gallons

5 0
3 years ago
What is the product of -2x^3+x-5 and x^3-3x-4 ?
murzikaleks [220]
To find the product of <span>-2x^3+x-5 and x^3-3x-4, we need to multiply each term in the first polynomial by the second polynomial. (So, x^3 - 3x - 4) times ....
-2x^3 = -2x^6 + 6x^4 + 8x^3
x = x^4 - 3x^2 - 4x
-5 = -5x^3 + 15x + 20
If we add all these together, we get (-2x^6 + 7x^4 + 3x^3 - 3x^2 + 11x + 20)</span>
6 0
3 years ago
Marco is selling floral arrangements. Each arrangement uses 1 vase and 11 orchids. Each vase costs Marco $4.00. Let C be the tot
Vadim26 [7]

Answer:

C

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
The force of gravity on Mars is different than on Earth. The function of the same situation on Mars would be represented by the
sweet-ann [11.9K]

Answer:

If thrown up with the same speed, the ball will go highest in Mars, and also it would take the ball longest to reach the maximum and as well to return to the ground.

Step-by-step explanation:

Keep in mind that the gravity on Mars; surface is less (about just 38%) of the acceleration of gravity on Earth's surface. Then when we use the kinematic formulas:

v=v_0+a\,*\,t\\y-y_0=v_0\,* t + \frac{1}{2} a\,\,t^2

the acceleration (which by the way is a negative number since acts opposite the initial velocity and displacement when we throw an object up on either planet.

Therefore, throwing the ball straight up makes the time for when the object stops going up and starts coming down (at the maximum height the object gets) the following:

v=v_0+a\,*\,t\\0=v_0-g\,*\,t\\t=\frac{v_0}{t}

When we use this to replace the 't" in the displacement formula, we et:

y-y_0=v_0\,* t + \frac{1}{2} a\,\,t^2\\y-y_0=v_0\,(\frac{v_0}{g} )-\frac{g}{2} \,(\frac{v_0}{g} )^2\\y-y_0=\frac{1}{2} \frac{v_0^2}{g}

This tells us that the smaller the value of "g", the highest the ball will go (g is in the denominator so a small value makes the quotient larger)

And we can also answer the question about time, since given the same initial velocity v_0 , the smaller the value of "g", the larger the value for the time to reach the maximum, and similarly to reach the ground when coming back down, since the acceleration is smaller (will take longer in Mars to cover the same distance)

3 0
3 years ago
Help on number 12 please?​
zloy xaker [14]

Answer:

f(n)= 5 · 4

f(n) = 5 \times 4 ^{n - 1}

Step-by-step explanation:

You use the explicit formula for geometric sequence. The five is the firat term and is placed correctly. The 4 is the rate of change, because if you multiply 5 by 4 you get 20 and so on.

7 0
4 years ago
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