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3 years ago

Please help!!!

Mathematics

2 answers:

makvit [3.9K]3 years ago

8 0

Answer:

The equation that can be solved using the expression is:

B. $10x^2+3x=2$

Step-by-step explanation:

We know that for any quadratic equation of the type:

$ax^2+bx+c=0$

The solution for 'x' is given by the formula:

$x=\dfrac{-b\pm \sqrt{b^2-4\times a\times c}}{2a}$

Hence, by comparing the given expression with the formula we see that:

b=3, a=10 and c= -2

Hence, we have the quadratic equation as:

$10x^2+3x-2=0$

or it can also be represented as:

$10x^2+3x=2$

Hence, option: B is the correct answer.

Debora [2.8K]3 years ago

7 0

Answer:

its B

Step-by-step explanation:

thanks

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slega [8]

Answer:

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Step-by-step explanation:

Since triangle CAN = triangle RUG

This means

C=R

A=U

N = G

We can change the order of the letters for the triangle in the first, but then they have to be corresponding in the second

ANC = UGR

NCA = GRU

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2 years ago

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A department store sells logo shirts at an original price of $20. Every month that a shirt doesn’t sell, the store reduces the s

Tasya [4]

Given:
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First markdown month:
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Second markdown month
15 * 75% = 11.25

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3 years ago

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Find the measure of < B

Vinvika [58]

The measure of angle b is 25°.

Solution:

Given data:

The "L" shape angle is a right angle.

Right angle is splitted by another line and two angles are formed.

One angle is 65° and the other angle is b.

Let us find the other angle b.

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3 years ago

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3 years ago

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Serjik [45]

(4x - 3)(2x - 1) ≥ 0

First, find the zeros:

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x = $\frac{3}{4}$ x = $\frac{1}{2}$

Next, plot these points and choose test points on the outside and between the zeros:

←-------0------ $\frac{1}{2}$ ------ $\frac{5}{8}$ ------ $\frac{3}{4}$ ------1------→

Lastly, plug in the test points and look for a positive result (since it is greater than 0).

Test Point 0: [4(0) - 3][2(0) - 1] = ( - )( - ) = + THIS WORKS!

Test Point $\frac{5}{8}$ : [4( $\frac{5}{8}$ ) - 3][2( $\frac{5}{8}$ ) - 1] = ( - )( + ) = - <em>This does NOT work</em>

Test Point 1: [4(1) - 3][2(1) - 1] = ( + )( + ) = + THIS WORKS!

Answer: x ≤ $\frac{1}{2}$ or x ≥ $\frac{3}{4}$

Interval Notation: (-∞, $\frac{1}{2}$ ] U [ $\frac{3}{4}$ , ∞)

Graph: ←------ $\frac{1}{2}$ $\frac{3}{4}$ --------→

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3 years ago