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3 years ago

Please help!!!

Mathematics

2 answers:

makvit [3.9K]3 years ago

8 0

Answer:

The equation that can be solved using the expression is:

B. $10x^2+3x=2$

Step-by-step explanation:

We know that for any quadratic equation of the type:

$ax^2+bx+c=0$

The solution for 'x' is given by the formula:

$x=\dfrac{-b\pm \sqrt{b^2-4\times a\times c}}{2a}$

Hence, by comparing the given expression with the formula we see that:

b=3, a=10 and c= -2

Hence, we have the quadratic equation as:

$10x^2+3x-2=0$

or it can also be represented as:

$10x^2+3x=2$

Hence, option: B is the correct answer.

Debora [2.8K]3 years ago

7 0

Answer:

its B

Step-by-step explanation:

thanks

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Step-by-step explanation:

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Please help me with this.

inna [77]

Answer:

Plot and connect (5,4), (3,0) and (7,0).

Step-by-step explanation:

This is in factored form and can be graphed directly from the equation. The equation shows the x-intercepts.

The x-intercepts are found by solving for x using the zero product rule.

(x-3)=0 so x = 3

(x-7) = 0 so x = 7

The intercepts are (3,0) and (7,0). Plot the points. The vertex will occur halfway between these points. 7-3 / 2 = 4/2 = 2. This means the axis of symmetry is at x = 5 and this is the x-coordinate of the vertex too.

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3 0

3 years ago

normally distributed with mean 24.6 seconds and standard deviation 0.64 seconds;the lower finishing time, the better. If the qua

marshall27 [118]

Answer:

$z=1.04$

And if we solve for a we got

$a=24.6 +1.04*0.64=25.27$

So the value of height that separates the bottom 85% of data from the top 15% is 25.27.

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".

Solution to the problem

Let X the random variable that represent the finishing time of a population, and for this case we know the distribution for X is given by:

$X \sim N(24.6,0.64)$

Where $\mu=24.6$ and $\sigma=0.64$

Solution to the problem

For this part we want to find a value a, such that we satisfy this condition:

$P(X>a)=0.15$ (a)

$P(X$ (b)

Both conditions are equivalent on this case. We can use the z score again in order to find the value a.

As we can see on the figure attached the z value that satisfy the condition with 0.85 of the area on the left and 0.15 of the area on the right it's z=1.04. On this case P(Z<1.04)=0.85 and P(z>1.04)=0.15

If we use condition (b) from previous we have this:

$P(X$