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Vaselesa [24]
3 years ago
14

A circle is centered at (11, −9) and has a radius of 12.

Mathematics
1 answer:
mamaluj [8]3 years ago
8 0
So the formula is: (x-h)^2+(y-k)^2=r^2

(x-11)^2+(y+9)^2=144

:)
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Hallar el volumen de un cubo de 4u. de arista
suter [353]
Yes because you is right
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3 years ago
Mark wants to use a grid like the ones in exercise 1 and 2 to model the percent equialent of the fraction 2/3. how many grid squ
artcher [175]
The fraction is 2/3
So, there should be 100 squares.
Next, the 100 squares is divided into 3 by vertical lines. The lines will not coincide with the sides of the squares. This is okay. Next, the 2 out of 3 will be shaded, this will be equivalent to 66 squares and one more square but it will not be filled up completely. In percent form, the fraction is 66.67%.
6 0
3 years ago
1. Quadrilateral EFGH is an isosceles trapezoid. If mG is four times mH, what is mE? A)18° C)72° D)144° B)36°​
Maslowich

Answer:

<E = 36 degrees (Answer B)

Step-by-step explanation:

Recall that the addition of all internal angles in a quadrilateral must equal 360 degrees. Then we can write the equation that states this as:

<E + <F + <G + <H = 360

Notice as well that we are dealing with an isosceles trapezoid, so there is a symmetry along the line that passes through the midpoints of sides FG and EH (the two bases). That means that the measures of angles <F = <G  and <E = <H .

The previous equation then can be written as:

<H + <G + <G + <H = 360

Also, since we are told that <G = 4 <H, we can use this info in the equation as shown below:

<H + 4 <H + 4 <H + <H = 360

10 <H = 360

divide both sides by 10 to isolate <H

<H = 360 / 10

<H = 36

Since as we mentioned, <E equals <H, we can state that

the measure of <E = 36 degrees (Answer B)

3 0
3 years ago
Which of the following lit all the interger solution of the inequalithy |X| &lt; 5
yulyashka [42]
|x|∈{0,1,2,3,4}
x∈{-4,-3,-2,-1,0,1,2,3,4}
3 0
3 years ago
Solve the following quadratic equation by using the quadratic formula.
Bas_tet [7]

Answer:

B. \frac{-3}{4}±\frac{\sqrt{41} }{4}

Step-by-step explanation:

First, substitute the equation into the quadratic formula.

x=\frac{b+-\sqrt{(b^{2} )-4(a)(c)} }{2a}

x=\frac{-3+-\sqrt{(3)^2-4(-2)(4)} }{4}

Solve for x.

x= \frac{-3+-\sqrt{9+32} }{4}

x=\frac{-3+-\sqrt{41} }{4}

The answer is x= -\frac{3}{4}±\frac{\sqrt{41} }{4}

6 0
3 years ago
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