Two lines are perpendicular if and only if the product of their slopes is - 1.
So, you just need to find the slope of each line and find out the product of their slopes.
I will do one example for you.
L1: y = 3x + 5
L2: y = - 3x + 14
L3: y = -x/3 + 14
The slope of a line is the coefficient of the x.
So the slopes are:
L1: slope 3
L2: slope -3
L3: slope -1/3
So now multiply the slopes of each pair of lines:
L1 and L2: 3 * (-3) = - 9 => No, they are not perpendicular
L2 and L3: (-3) * (-1/3) = 1 => No, they are not perpendicular
L1 and L3: (3) * (-1/3) = -1 => Yes, they are penpendicular.
Answer:
ok so jacob threw 1/5 of x
Step-by-step explanation:
if you say julien threw x and jacob threw 1/5 of that than jacob threw 1/5 of x
Answer:
a
Step-by-step explanation:
Answer:
(x−3)(x−5)
Step-by-step explanation:
Hope this helped
Q in (-oo:+oo)
2/3 = (1/3)*q // - (1/3)*q
2/3-((1/3)*q) = 0
ddddddddd
d d
d d
(-1/3)*q+2/3 = 0 d d
d d
2/3-1/3*q = 0 // - 2/3 d d
d d
-1/3*q = -2/3 // : -1/3 d d
d d
q = -2/3/(-1/3) ddddddd dddddddd
dd dd
q = 2 dd dd
dd dddd dd
q = 2 dddddddddd dddddddddddd
