All categories

3 years ago

What is 1/8 of the sum of 28 and 43

Mathematics

1 answer:

victus00 [196]3 years ago

3 0

1/8 of anything is just 1/8 * anything, so $\bf \cfrac{1}{8}\times (28+43)$

You might be interested in

Simplify. 4 × (8 + 5) + 9 45 46 61 62

Darya [45]

Answer:

Step-by-step explanation:

4 × (8 + 5) + 9

Parentheses first

4 × (13) + 9

Then multiply

52 +9

Then add

7 0

3 years ago

Find p[b] in each case: (a) events a and b are a partition and p[a] = 3p[b]. (b) for events a and b, p[a ∪ b] = p[a] and p[a ∩ b

nirvana33 [79]

Answer:

Case(a): $p[b]=\frac{1}{3}p[a]$

Case(b): $p[b]=0$

Case(c): $p[b]=\frac{1}{2}p[a\cap b]$

Step-by-step explanation:

Given

(a) events a and b are a partition and p[a] = 3p[b].

(b) for events a and b, p[a ∪ b] = p[a] and p[a ∩ b] = 0.

we have to find the p[b] in each case:

Case (a): events a and b are a partition and p[a] = 3p[b].

gives $p[b]=\frac{1}{3}p[a]$

Case (b): for events a and b, p[a ∪ b] = p[a] and p[a ∩ b] = 0.

$p[a\cup b]=p[a]$ ⇒ $p[a]+p[b]-p[a\cap b]=p(a)$ ⇒ $p[b]=0$ ∵ p[a ∩ b] = 0.

Case(3): for events a and b, p[a ∪ b] = p[a]− p[b].

p[a ∪ b] = p[a]− p[b]

⇒ $p[a]+p[b]-p[a\cap b]=p[a]-p[b]$

⇒ $2p[b]=p[a\cap b]$

⇒ $p[b]=\frac{1}{2}p[a\cap b]$

4 0

3 years ago

Read 2 more answers

Please help me with this question 17t 200kg divided by 8

garri49 [273]

Answer:

1 ton = 1000 kg

So, 17 ton = 17 × 1000

= 17000 kg

17000 + 200 kg = 17200 kg

$\frac{17200}{8} = 2150kg$

5 0

3 years ago

Kathie ran for twice as long as she walked. She walked for 10 minutes more than she rode her bike. She walked for 30 minutes.

Gnoma [55]

30 x 2 = 60 min running
30 - 10= 20 min biking

30+60+20=110 min, or an hour and 50 minutes

7 0

4 years ago

To snails are 189 cm apart. They crawl towards each other at rates that differ by 1 cm a minute. After 27 minutes they meet. How

Stella [2.4K]

Speed of snail 1 = 3.795 cm/minute

Speed of snail 2 = 4.795 cm/minute

Solution:

Given that,

Total distance = 189 cm

They crawl towards each other at rates that differ by 1 cm a minute

Let the speed of snail 1 be "x"

Let the speed of snail 2 be "x + 1"

Total time = 22 minutes

Since the snails are moving towards each other,

Speed = x + x + 1 = 2x + 1

How fast is each snail crawling?

$Distance = speed \times time\\\\189 = 2x + 1 \times 22\\\\189 = 44x + 22\\\\44x = 189 - 22\\\\44x = 167\\\\x = 3.795$

Thus,

Speed of snail 1 = 3.795 cm/minute

Speed of snail 2 = 3.795 + 1 = 4.795 cm/minute

7 0

3 years ago