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Lilit [14]
3 years ago
15

Set up the following additional using a vertical format and find the sum of the given polynomials:

Mathematics
2 answers:
Dima020 [189]3 years ago
8 0
Not sure about this one
Sholpan [36]3 years ago
8 0

Answer:

Step-by-step explanation:

The Answer is 10

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Find the sum of one thousand and forty-two, sixty-nine and five hundred and thirty-six.
Viefleur [7K]

Answer:

1042

69+5=74

100+36=16

Step-by-step explanation:

> one thousand = 1000 (thousandth place)

0 = hundred place

and fourty-two = 42 (tenths)

1042

> 69+5=74

sixty-nine = 69 (tenth place)

5 = (unit)

64

> 100+36=536

one hundred = 100(hundredth place)

36 ( tenths)

146

7 0
3 years ago
The mean of a sequence of n numbers is m. If we split the sequence into two sequences of lengths n1 and n2 and compute their mea
Furkat [3]

The mean of a sequence of numbers is the average.

The true statement is: \mathbf{mn = m_1 \times n_1 + m_2 \times n_2}

The given parameters are:

\mathbf{Mean = m}

\mathbf{Size = n}

The mean of a dataset is calculated as:

\mathbf{Mean = \frac{\sum x}{Size}}

So, we have:

\mathbf{m = \frac{\sum x}{n}}

Multiply both sides by m

\mathbf{\sum x = mn}

When the sequence is split into two, we have:

\mathbf{\sum x_1 = m_1\times n_1}

\mathbf{\sum x_2 = m_2\times n_2}

Where:

\mathbf{\sum x_ = \sum x_1 + \sum x_2}

So, we have:

\mathbf{mn = m_1 \times n_1 + m_2 \times n_2}

Hence, the true statement is: \mathbf{mn = m_1 \times n_1 + m_2 \times n_2}

Read more about mean and averages at:

brainly.com/question/16217700

8 0
3 years ago
( 3 /4 ÷ 3 /100 −47/2 )÷4/2 · 2 /3 +7/6
slava [35]
Lol this answer:
(3/4÷3/100-47/2)÷4/2.2/3+7/6
(3/4.100/3-47/2).2/4.2/3+7/6
(25-47/2).2/2.1/3+7/6
3/2.2/2.1/3+7/6
1/2+7/6
5
_
3
```2
1
` —
` 3
8 0
4 years ago
1
Digiron [165]

Answer:

105°

Step-by-step explanation:

105°

7 0
3 years ago
PLEASE HELP SMART PEOPLE! <br>This is add/subtract polynomials. <br>h(x)+g(x)<br>h(x)=6x^2+4x^4+7x​
luda_lava [24]

Given,

h(x) =  {6x}^{2}  +  {4x}^{4}  + 7x

g( x) =  {6x}^{2}  - 4x +  {3x}^{4}

Therefore,

h(x) + g(x)

( {6x}^{2}  +  {4x}^{4}  + 7x) + ({6x}^{2}  - 4x +  {3x}^{4})

{6x}^{2}  +  {4x}^{4}  + 7x + {6x}^{2}  - 4x +  {3x}^{4}

(4 {x}^{4}  + 3 {x}^{4} ) + ( {6x}^{2}  +  {6x}^{2} ) + (7x - 4x)

{7x}^{4}  +  {12x}^{2}  + 3x

4 0
3 years ago
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