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Nimfa-mama [501]

3 years ago

6

Lori downloaded all the pictures she took at Rita’s wedding into a single computer folder. She took 86 of the 134 pictures with

her camera and the remainder of them with her cell phone. Of the pictures Lori took with her cell phone, one out of every five was blurry.
To the nearest whole percent, what is the probability that when she opens a random picture from the computer folder, it will be a blurry picture she took with her cell phone?

2 answers:

ololo11 [35]3 years ago

3 0

I believe that it would be roughly 31%

julsineya [31]3 years ago

3 0

<h2>Answer:</h2>

The answer is 7%.

<h2>Step-by-step explanation:</h2>

Total number of pictures = 134

Number of pictures in camera = 86

Remaining number of pictures in cell phone = $134-86=48$

Given is, of the pictures Lori took with her cell phone, one out of every five was blurry.

Means $\frac{1}{5}$ of the 48 pictures in the cell phone cell phone were blurry.

Now this 48 pictures were taken from a lot of 134 pictures.

So, the probability that when Lori opens a random picture from the computer folder, it will be a blurry picture she took with her cell phone is :

$\frac{1}{5}*\frac{48}{134}$ =0.0716

For percentage, multiply this by 100, we get:

$0.0716*100=7.16$ %

Rounding this to the nearest whole percent, we have 7%.

Therefore, the answer is 7%.

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Inessa05 [86]

Answer:

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Step-by-step explanation:

4 0

2 years ago

A book sold 41,900 copies in its first month of release. Suppose this represents 8.1% of copies sold to date. How many copies ha

babymother [125]

517284 books have been sold to date.

Step-by-step explanation:

Given,

Copies sold in first month = 41900

This represents 8.1% of copies sold to date.

Let,

x be the number of copies that have been sold to date.

8.1% of x = 41900

$\frac{8.1}{100}*x=41900\\0.081x=41900\\$

Dividing both sides by 0.081

$\frac{0.081x}{0.081}=\frac{41900}{0.081}\\x=517283.95$

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x = 517284

517284 books have been sold to date.

Keywords: percentage, division

Learn more about division at:

#LearnwithBrainly

3 0

3 years ago

In the past year Ahmad watched 52 movies that he thought were very good. He watched 80 movies over the whole year. Of the movies

jok3333 [9.3K]

He rated 65% of the movies good

5 0

3 years ago

Human visual inspection of solder joints on printed circuit boards can be very subjective. Part of the problem stems from the nu

olga_2 [115]

Answer:

a

The probability that the selected joint was judged to be defective by neither of the two inspectors is $P(A' n B' ) = 0.8855$

b

The probability that the selected joint was judged to be defective by inspector B but not by inspector A is $P(A' n B) =0.0403$

Step-by-step explanation:

From the question we are told that

The sample size is $n_s = 10000$

The number of outcome for inspector A is $n__{A}} = 742$

The number of outcome for inspector B is $n__{B}} = 745$

The number of joints judged defective by both inspector is $n(A u B) = 1145$

The the probability that the selected joint was judged to be defective by neither of the two inspectors is mathematically represented as

$P(A' n B' ) = 1 - P(A u B)$

Now

$P(A\ u \ B) = \frac{n(Au B)}{n_s }$

substituting values

$P(A\ u \ B) = \frac{1145}{ 10 000 }$

So

$P(A' n B' ) = 1 - \frac{1145}{10 000}$

$P(A' n B' ) = 0.8855$

the probability that the selected joint was judged to be defective by inspector B but not by inspector A is mathematically represented as

$P(A' n B) = P(A \ u \ B) -P(A)$

Now

$P(A) = \frac{n__{A}}{n_s}$

substituting values

$P(A) = \frac{742}{10 000}$

So

$P(A' n B) = \frac{1145}{10 000} - \frac{742}{10 000}$

$P(A' n B) =0.0403$

7 0

4 years ago

A concession stand sells 50 drinks, of which 17 are orange juice. What is the probability that the next drink sold will be orang

ra1l [238]

34% because...
17/50 times 2= .34= 34%

7 0

3 years ago