Answer:
The hourly pay for the lifeguards in 2001 was of $6.31.
Step-by-step explanation:
The hourly pay, in dollars, in t years after 1995, is given by the following equation:
What was the hourly pay for the lifeguards in 2,001?
2001 is 2001 - 1995 = 6 years after 1995. So this is P(6).
The hourly pay for the lifeguards in 2001 was of $6.31.
where is the rest of the information?
Answer:
60%
Step-by-step explanation:
he gave away 2/5 which is 40%. 100%-40% is 60%
Taking the same test right now....I think the answer is 4.5. Hope that helps!
Answer:
$6261.61
Step-by-step explanation:
The solution to the differential equation is the exponential function ...
A(t) = 5000e^(0.0225t)
We want the account value after 10 years:
A(10) = 5000e^(0.225) = 6261.61
The value of the account after 10 years will be $6,261.61.
_____
The rate of change equation basically tells you that interest is compounded continuously. After working interest problems for a while you know the formula for that is the exponential formula A = A0·e^(rt).
Or, you can solve the differential equation using separation of variables:
dA/A = 0.0225dt
ln(A) = 0.0225t +C . . . . integrate
A(t) = A0·e^(0.0225t) = 5000·e^(0.0225t) . . . . solution for A(0) = 5000
