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3 years ago

What is the solution of the equation? Eliminate any extraneous solutions √3x + 28 - 8 = x

Mathematics

1 answer:

Alecsey [184]3 years ago

6 0

The answer to the solution is x=43+√249/2

I hope this helps.

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Ms. Kork sold her car for $8700. This was $100 more than two fifths of what she had paid for the car originally. How much mad Ms

Ne4ueva [31]

Answer:

8600 is 100 less

3440?

Step-by-step explanation:

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3 years ago

How many sides does a regular polygon have if each of its interior angles is 165 degree.

hoa [83]

24
Complete step-by-step answer:
Thus, the regular polygon with interior angle each measuring 165∘ is a 24-sided polygon.

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3 years ago

Aflati triunghiul dreptunghic ABC daca a) a=17 si b=8<br> b) c=6<br> C=42 grade

Ierofanga [76]

Answer is c c=42 grade

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3 years ago

A 12 foot ladder is placed 5 feet from the base of the building. About how high does the ladder reach?

Mariulka [41]

Answer:

7 foot

Step-by-step explanation:

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3 years ago

A rectangular box is to have a square base and a volume of 12 ft3. If the material for the base costs $0.17/ft2, the material fo

katen-ka-za [31]

Answer:

(a)Length =2 feet

(b)Width =2 feet

(c)Height=3 feet

Step-by-step explanation:

Let the dimensions of the box be x, y and z

The rectangular box has a square base.

Therefore, Volume of the box $V=x^2z$

Volume of the box $=12 ft^3\\$

$Therefore, x^2z=12\\z=\frac{12}{x^2}$

The material for the base costs $\$0.17/ft^2$ , the material for the sides costs $\$0.10/ft^2$ , and the material for the top costs $\$0.13/ft^2$ .

Area of the base $=x^2$

Cost of the Base $=\$0.17x^2$

Area of the sides $=4xz$

Cost of the sides= $=\$0.10(4xz)$

Area of the Top $=x^2$

Cost of the Base $=\$0.13x^2$

Total Cost, $C(x,z) =0.17x^2+0.13x^2+0.10(4xz)$

Substituting $z=\frac{12}{x^2}$

$C(x) =0.17x^2+0.13x^2+0.10(4x)(\frac{12}{x^2})\\C(x)=0.3x^2+\frac{4.8}{x} \\C(x)=\dfrac{0.3x^3+4.8}{x}$

To minimize C(x), we solve for the derivative and obtain its critical point

$C'(x)=\dfrac{0.6x^3-4.8}{x^2}\\Setting \:C'(x)=0\\0.6x^3-4.8=0\\0.6x^3=4.8\\x^3=4.8\div 0.6\\x^3=8\\x=\sqrt[3]{8}=2$

Recall: $z=\frac{12}{x^2}=\frac{12}{2^2}=3\\$

Therefore, the dimensions that minimizes the cost of the box are:

(a)Length =2 feet

(b)Width =2 feet

(c)Height=3 feet

7 0

3 years ago