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3 years ago

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During dance practice, Sasha drank 21⁄2 pints of water, and on the way home she drank 1⁄2 cup of water. How much water did she d

rink in total?
cups and
ounces

1 answer:

Flura [38]3 years ago

5 0

Try adding the two and think of it mentally as if you were drinking the amount of cups of water that's what I do when I have questions like these :))

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An uber charges a flat rate of $6 plus $1.25 per mile. Kayla can spend no more than $27.50. If she wants to tip her driver $4, w

Lynna [10]

Answer:

The cost of the uber is a $6 flat rate plus $1.25 per mile.

Then if you take an uber for x miles, the cost will be:

c(x) = $1.25*x + $6

Now, in this case Kayla also wants to add a tip of $4, then the total cost will be:

c(x) = $1.25*x + $6 + $4 = $1.25*x + $10

And we have the restriction that Kalya can't spend more than $27.50

Then the cost must be equal or smaller than $27.50, we can write this as:

c(x) ≤ $27.50

$1.25*x + $10 ≤ $27.50

Whit the above equation we can find the maximum value of x if we isolate x in one side of the inequality.

$1.25*x + $10 ≤ $27.50

$1.25*x ≤ $27.50 - $10

$1.25*x ≤ $17.50

x ≤ ($17.50/$1.50)

x ≤ 11.67

So the maximum number of miles that she can travel on that uber is 11.67 miles, but in this cases we only work with whole numbers, so we should round it to the next whole number that meets the condition, which is 11.

x = 11

The maximum number of miles that she can travel on that uber is 11 miles.

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3 years ago

please help me, Prove a quadrilateral with vertices G(1,-1), H(5,1), I(4,3) and J(0,1) is a rectangle using the parallelogram me

mestny [16]

Answer:

Step-by-step explanation:

We are given the coordinates of a quadrilateral that is G(1,-1), H(5,1), I(4,3) and J(0,1).

Now, before proving that this quadrilateral is a rectangle, we will prove that it is a parallelogram. For this, we will prove that the mid points of the diagonals of the quadrilateral are equal, thus

Join JH and GI such that they form the diagonals of the quadrilateral.Now,

JH= $\sqrt{(5-0)^{2}+(1-1)^{2}}=5$ and

GI= $\sqrt{(4-1)^{2}+(3+1)^{2}}=5$

Now, mid point of JH= $(\frac{x_{1}+x_{2}}{2},\frac{y_{1}+y_{2}}{2})$

= $(\frac{5+0}{2},\frac{1+1}{2})=(\frac{5}{2},1)$

Mid point of GI= $(\frac{5}{2},1)$

Since, mid point point of JH and GI are equal, thus GHIJ is a parallelogram.

Now, to prove that it is a rectangle, it is sufficient to prove that it has a right angle by using the Pythagoras theorem.

Thus, From ΔGIJ, we have

$(GI)^{2}=(IJ)^{2}+(JG)^{2}$ (1)

Now, JI= $\sqrt{(4-0)^{2}+(3-1)^{2}}=\sqrt{20}$ and GJ= $\sqrt{(0-1)^{2}+(1+1)^{2}}=\sqrt{5}$

Substituting these values in (1), we get

$5^{2}=(\sqrt{20})^{2}+(\sqrt{5})^{2} }$

$25=20+5$

$25=25$

Thus, GIJ is a right angles triangle.

Hence, GHIJ is a rectangle.

Also, The diagonals GI= $\sqrt{(4-1)^{2}+(3+1)^{2}}=5$ and HJ= $\sqrt{(0-5)^2+(1-1)^2}=5$ are equal, thus, GHIJ is a rectangle.

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3 years ago

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alina1380 [7]

Answer:

y=5 m=3

Step-by-step explanation:

i mean it shows you the y intercept and the slope and the linear function all in that one picture

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Five plus twice a number is thirty-one

igomit [66]

5 + 2n = 31
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