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garri49 [273]
3 years ago
13

PLEASE HELP ASAP AND NO VIRS!

Mathematics
1 answer:
Kay [80]3 years ago
6 0

Answer:

C) 84

Step-by-step explanation:

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Determining Sine and Cosine Values
marysya [2.9K]

Is there an attachment?

6 0
3 years ago
after 8% discount from the list price, the sale price price of a poster was $17.48. what was the list price of poster.
Ludmilka [50]
Well the answer would be $18.8784 but if you want it to be shorter it would be $18.88 because you multiply 17.48 and 0.08 and get 1.3984 and then you add it to $17.48
6 0
3 years ago
In 1980 (before the era of in-vitro fertilization), there were 3,612,258 births in the United States (according to the U.S. Cens
scoray [572]

Answer:

There was a 1.93% probability of having multiples (twins or more) in 1980.

Step-by-step explanation:

There were 3,612,258 births in the US in 1980.

Of those,

68339 + 1337 = 69676 were multiplies.

So

What was the probability of having multiples (twins or more) in 1980?

P = \frac{69676}{3612258} = 0.0193

There was a 1.93% probability of having multiples (twins or more) in 1980.

8 0
2 years ago
A store received a shipment of soup cans. The clerk put an equal number of cans on each of 4 shelves. Write an equation to repre
icang [17]
To represent the number of cans in each shelf you will divide the total number of cans by the number of shelves.

This is represented as
t/4 = n.
8 0
3 years ago
Read 2 more answers
15y^-11/3y^-11, show steps I need help please don't understand how to do it.
tester [92]
One may note, you never quite asked anything per se, ahemm, if you meant simplification.

\bf \left.\qquad \qquad \right.\textit{negative exponents}\\\\
a^{-{ n}} \implies \cfrac{1}{a^{ n}}
\qquad \qquad
\cfrac{1}{a^{ n}}\implies a^{-{ n}}
\qquad \qquad 
a^{{{  n}}}\implies \cfrac{1}{a^{-{{  n}}}}\\\\
-------------------------------\\\\
\cfrac{15y^{-11}}{3y^{-11}}\implies \cfrac{15}{3}\cdot \cfrac{y^{-11}}{y^{-11}}\implies 5\cdot y^{-11}\cdot y^{+11}\implies 5\cdot y^{-11+11}
\\\\\\
5y^0 \implies \boxed{5}
8 0
3 years ago
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