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Marina CMI [18]
3 years ago
13

Help me and i’ll mark you brainliest plus you get 20 points !!!!

Mathematics
1 answer:
Anton [14]3 years ago
6 0

Answer:

Angle bisector

Step-by-step explanation:

Find the measure of the angle COA. By angle addition postulate,

m\angle COX=m\angle AOX+m\angle COA

From the diagram,

m\angle COX=80^{\circ}\\ \\m\angle AOX=40^{\circ},

then

80^{\circ}=m\angle COA+40^{\circ}\\ \\m\angle COA=80^{\circ}-40^{\circ}=40^{\circ}

Find the measure of the angle BOA. By angle addition postulate,

m\angle BOX=m\angle AOX+m\angle BOA

From the diagram,

m\angle BOX=60^{\circ}\\ \\m\angle AOX=40^{\circ},

then

60^{\circ}=m\angle BOA+40^{\circ}\\ \\m\angle BOA=60^{\circ}-40^{\circ}=20^{\circ}

Find the measure of the angle COB. By angle addition postulate,

m\angle COX=m\angle BOX+m\angle COB

From the diagram,

m\angle BOX=60^{\circ}\\ \\m\angle COX=80^{\circ},

then

80^{\circ}=m\angle COB+60^{\circ}\\ \\m\angle COB=80^{\circ}-60^{\circ}=20^{\circ}

This means, the measures of angles COB and BOA are the same and are equal half the measure of angle COA, so angles COB and BOA are congruent. This means, the ray OB is the angle bisector of angle COA

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