B is the answer to the question
4/5 because 12/15 was simplified using 3.
Answer:
The expected number of the people at the reception whose favorite snack will be chips is 1152
Step-by-step explanation:
Given
The data in the above table and
Reception = 3600
Required
Predict the number of the people at the reception whose favorite snack will be chips.
The first step is to determine the total number of samples;



The next step is to determine the fraction of people whose favorite is chips


The product of the above fraction and the expected number of people in the reception is the solution to this question;




<em>Hence, the expected number of the people at the reception whose favorite snack will be chips is 1152</em>
Answer:

Step-by-step explanation:
Given that,
In an AP, the 6th term is 39 i.e.

In the same AP, the 19th term is 7.8 i.e.

Subtract equation (1) from (2).
7.8 - 39 = a+18d - (a+5d)
-31.2 = a +18d-a-5d
-31.2 = 13d
d = -2.4
Put the value of d in equation (!).
39 = a+5(-2.4)
39 = a- 12
a = 39+12
a = 51
The sum of n terms of an AP is given by :
![S_n=\dfrac{n}{2}[2a+(n-1)d]](https://tex.z-dn.net/?f=S_n%3D%5Cdfrac%7Bn%7D%7B2%7D%5B2a%2B%28n-1%29d%5D)
Put n = 25 and respected values,
![S_{25}=\dfrac{25}{2}[2(51)+24(-2.4)]\\\\=555](https://tex.z-dn.net/?f=S_%7B25%7D%3D%5Cdfrac%7B25%7D%7B2%7D%5B2%2851%29%2B24%28-2.4%29%5D%5C%5C%5C%5C%3D555)
Hence, the sum of first 25 terms of the AP is equal to 555.