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Natali [406]
3 years ago
12

Someone help pls :((

Mathematics
1 answer:
harina [27]3 years ago
6 0

Answer:

56.714°

Step-by-step explanation:

Since we do not have a full angle of this proposed triangle, we must do this by splitting it into two right triangles instead of using the law of sines.

250m*sin(40°) = 250m*0.64278760968 = 160.696902422m

452.4m-160.696902422m=291.703097578m

Use pythagorean theorem:

\sqrt{250^2 - 160.696902422^2}

62500-25823.494448025787=36676.505552

\sqrt{36676.505551974216} = 191.511110779m

arctan(291.703097578m/191.511110779m)≈56.714°

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This equation has no solution where 'a' and 'b'
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You said                                 2a + 2b = 2a

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'b' must be zero.

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3 years ago
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FromTheMoon [43]

Answer:

1,2,5 No 3,4 Yes

Step-by-step explanation:

x(x^2-5) No

x(x^2-25x) No

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Write the fraction as the product of a whole number and. Unit fraction 2/5
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Step-by-step explanation:

divide 2 and 5

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3 years ago
Describe the end behavior of the function:<br> f(x) = 1/2*2^x +3
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Suppose in the University of Manitoba, 40% of the students live in apartments. If 600 students are randomly selected, then the a
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Answer:

P(200\leq X\leq 400)=P(\frac{200-240}{12}\leq \frac{X-\mu}{\sigma}\leq \frac{400-240}{12})=P(-3.33\leq Z \leq 13.33)

=P(Z

So then the correct answer would be:

B) .9996

Step-by-step explanation:

The exact way to solve this problem is using the binomial distribution, assuming that our random variable of interest is "number of students living in apartments" represented by X and X \sim Bin(n=600, p =0.4)

And we want this probability:

P(200 \leq X \leq 400) [tex]In order to find this probability we can use the foloowing excel code:"=BINOM.DIST(400,600,0.4,TRUE)-BINOM.DIST(199,600,0.4,TRUE)"And we got:[tex] P(200 \leq X \leq 400) =0.999675[tex]But for this case the problem says that we need to approximate, so then we can use the normal approximation to the normal distribution. We need to check the conditions in order to use the normal approximation.&#10;[tex]np=600*0.4=240\geq 10

n(1-p)=600*(1-0.4)=360 \geq 10

So we see that we satisfy the conditions and then we can apply the approximation.

If we appply the approximation the new mean and standard deviation are:

E(X)=np=600*0.4=240

\sigma=\sqrt{np(1-p)}=\sqrt{600*0.4(1-0.4)}=12

And then X \sim N (\mu = 240, \sigma= 12)

And we are interested on the following probability:

P(200\leq X\leq 400)=P(\frac{200-240}{12}\leq \frac{X-\mu}{\sigma}\leq \frac{400-240}{12})=P(-3.33\leq Z \leq 13.33)

=P(Z

So then the correct answer would be:

B) .9996

6 0
3 years ago
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