Answer:
hi taxes was waa Bynum waa Hitachi waa hug
Answer:
a=15
Step-by-step explanation:
By pythagoras' theorem
25²=20²+a²
625=400+a² group like terms
a²=625-400
a²=225

therefore a=15
Firstly make the f(x) = x and x = y:
x = y^2
Then solve for y:
√x = y
Hopefully this helps and let me know if you have more questions!
Answer:
10,000,000
Step-by-step explanation:
ten million
The area of a traingle is

So we need to know the base and the height
To work out the sides of a right angle triangle we can use a²+b²=c
c is the hypotenuse and a and b are the other sides
Because this triangle is isoceles we know that a and b are the same
a²+b²=c²
a²+a²=c²
2a²=c²
2a²=(x√6)²
2a²=(x√6)(x√6)
2a²=x²+x√6+x√6+6
2a²=x²+x√6+x√6+6
a²=

a=

A=

A=

A=

×

×

A=

×

A=