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3 years ago

8

Can you use the SAS Postulate, the AAS Theorem, or both to prove the triangles congruent? A. either SAS or AAS B. SAS only C. AA

S only D. neithe

1 answer:

Harman [31]3 years ago

5 0

Sas only because the triangles and usually congruent to me or in my opponion

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What equation in slope-intercept form represents the line that passes through the points

Mumz [18]

<h2>Answer: y = - x + 1 </h2>

<h3>Step-by-step explanation: </h3>

For us to write the equation for this line, we need to (1) find the slope of the line, and (2) use one of the points to write an equation:

The question gives us two points, (-3, 4) and (2, -1), from which we can find the slope and later the equation of the line.

<u>Finding the Slope</u>

The slope of the line (m) = (y₂ - y₁) ÷ (x₂ - x₁)

= (4 - (- 1)) ÷ ((-3) - 2)

= - 1

<u>Finding the Equation</u>

We can now use the point-slope form (y - y₁) = m(x - x₁)) to write the equation for this line:

⇒ y - (-1) = - 1 (x - 2)

y + 1 = - (x - 2)

we could also transform this into the slope-intercept form ( y = mx + c) by making y the subject of the equation:

since y + 1 = - (x - 2)

∴ y = - x + 1

<em>To test my answer, I have included a Desmos Graph that I graphed using the information provided in the question and my answer.</em>

8 0

2 years ago

simplify the difference. (–7x – 5x4 5) – (–7x4 – 5 – 9x) a. 2x4 2x 10 b. –14x4 10x 10 c. –14x4 – 10x 10 d. 2x4 2x 8

11Alexandr11 [23.1K]

If you would like to simplify the difference <span>(–7x – 5x^4 + 5) – (–7x^4 – 5 – 9x), you can do this using the following steps:

</span><span>(–7x – 5x^4 + 5) – (–7x^4 – 5 – 9x) = -7x - 5x^4 + 5 + 7x^4 + 5 + 9x = 2x^4 + 2x + 10

The correct result would be </span><span>a. 2x^4 + 2x + 10.</span>

8 0

3 years ago

Help me and this question please please

disa [49]

Answer:

the things wont load whats the question?

Step-by-step explanation:

8 0

2 years ago

Find an explicit rule for the nth term of the sequence.The second and fifth terms of a geometric sequence are 18 and 144, respec

vova2212 [387]

Given:

second term = 18

fifth term = 144

The nth term of a geometric sequence is:

$\begin{gathered} a_n\text{ = ar}^{n-1} \\ Where\text{ a is the first term} \\ r\text{ is the common ratio} \end{gathered}$

Hence, we have:

$\begin{gathered} \text{ar}^{2-1}\text{ = 18} \\ ar\text{ = 18} \\ \\ ar^{5-1}=\text{ 144} \\ ar^4\text{ =144} \end{gathered}$

Divide the expression for the fifth term by the expression for the second term:

$\begin{gathered} \frac{ar^4}{ar}\text{ = }\frac{144}{18} \\ r^3\text{ = }\frac{144}{18} \\ r\text{ = 2} \end{gathered}$

Substituting the value of r into any of the expression:

$\begin{gathered} ar\text{ = 18} \\ a\text{ }\times\text{ 2 = 18} \\ Divide\text{ both sides by 2} \\ \frac{2a}{2}\text{ =}\frac{18}{2} \\ a\text{ = 9} \end{gathered}$

Hence, the explicit rule for the sequence is:

$a_n\text{ = 9\lparen2\rparen}^{n-1}$

5 0

1 year ago

Which value in the replacement set is a solution to this equation? 2n + 5 = 27 Replacement set: {11, 12, 13} Drag the solution i

Alchen [17]

11 is the answer to your question.

2×11=22

22+5=27

6 0

3 years ago