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3 years ago

Find the surface area of the triangular prism please.

Mathematics

1 answer:

Kobotan [32]3 years ago

3 0

Surface area = area of 3 rectangles + 2 triangles

= 3*(3*7) + 2 * ( 1/2 * 3 * 2.6)

= 63 + 2* 3.9

= 70.8 in^2

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A car traveling 118 miles uses 4 gallons of gas. At the rate, how many gallons will it use traveling 227 miles?

sashaice [31]

Answer:

b.7.69

Step-by-step explanation:

188/4=29.5

29.5 gal per mile

227/29.5=7.69

8 0

2 years ago

The equation of a given circle in general form is x^2+y^2-8x+12y+27=0. Write the equation in standard form, (x-h)^2+(y-k)^2=r^2,

umka2103 [35]

Answer:

(x - 4)² + (y + 6)² = 5²

Step-by-step explanation:

rearrange the general equation as follows

collect the terms in x and y together and place the constant on the right side

x² - 8x + y² + 12y = - 27

add (half the coefficient of the x/y term)² to both sides

x² + 2(- 4)x + y² + 2(6)y = - 27

(x - 4)² + 16 + (y + 6)² + 36 = - 27 + 16 + 36

(x - 4)² + (y + 6)² = 25

(x - 4)² + (y + 6)² = 5² ← in standard form

7 0

3 years ago

Six subtracted from a number

Klio2033 [76]

Answer:

X-6

Step-by-step explanation:

Represent the unknown number with a variable then introduce the minus sign

8 0

3 years ago

Given the following trigonometric ratio, enumerate the meaning ratio

Likurg_2 [28]

Answer:

The trigonometric ratios are presented below:

$\sin \theta = \frac{AC}{\sqrt{AC^{2} + BC^{2}}}$

$\cos \theta = \frac{BC}{\sqrt{AC^{2} + BC^{2}}}$

$\cot \theta = \frac{BC}{AC}$

$\sec \theta = \frac{\sqrt{AC^{2}+BC^{2}}}{BC}$

$\csc \theta = \frac{\sqrt{AC^{2}+BC^{2}}}{AC}$

Step-by-step explanation:

From Trigonometry we know the following definitions for each trigonometric ratio:

Sine

$\sin \theta = \frac{y}{h}$ (1)

Cosine

$\cos \theta = \frac{x}{h}$ (2)

Tangent

$\tan \theta = \frac{\sin \theta}{\cos \theta} = \frac{y}{x}$ (3)

Cotangent

$\cot \theta = \frac{\cos \theta}{\sin \theta} = \frac{x}{y}$ (4)

Secant

$\sec \theta = \frac{1}{\cos \theta} = \frac{h}{x}$ (5)

Cosecant

$\csc \theta = \frac{1}{\sin \theta} = \frac{h}{y}$ (6)

Where:

$x$ - Adjacent leg.

$y$ - Opposite leg.

$h$ - Hypotenuse.

The length of the hypotenuse is determined by the Pythagorean Theorem:

$h = \sqrt{x^{2}+y^{2}}$

If $y = AC$ and $x = BC$ , then the trigonometric ratios are presented below:

$\sin \theta = \frac{AC}{\sqrt{AC^{2} + BC^{2}}}$

$\cos \theta = \frac{BC}{\sqrt{AC^{2} + BC^{2}}}$

$\cot \theta = \frac{BC}{AC}$

$\sec \theta = \frac{\sqrt{AC^{2}+BC^{2}}}{BC}$

$\csc \theta = \frac{\sqrt{AC^{2}+BC^{2}}}{AC}$

6 0

3 years ago

-2x+9=9 solved y substitute

Varvara68 [4.7K]

Answer:

x=0

Step-by-step explanation:

-2x+9=9

-2x=9-9

-2x=0

x=0/-2

x=0

6 0

3 years ago