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Sloan [31]
4 years ago
10

Find the surface area of the triangular prism please.

Mathematics
1 answer:
Kobotan [32]4 years ago
3 0
Surface area =  area of 3 rectangles + 2 triangles

            =  3*(3*7) + 2 * ( 1/2 * 3 * 2.6)

            =   63 +   2* 3.9

            =   70.8  in^2

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Solve the system of equations for y. x - 5y = -6 and x + 2y = 8
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The lengths of a triangle are given below is the triangle obtuse acute or right ? 11,12,15
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Find the work done by the force field F(x, y) = xi + (y + 5)j in moving an object along an arch of the cycloid r(t) = (t − sin(t
Nimfa-mama [501]

Integrate the force field along the given path (call it <em>C</em>):

W=\displaystyle\int_C\mathbf F(x,y)\cdot\mathrm d\mathbf r=\int_0^{2\pi}\mathbf F(x(t),y(t))\cdot\frac{\mathrm d\mathbf r}{\mathrm dt}\,\mathrm dt

=\displaystyle\int_0^{2\pi}\bigg((t-\sin t)\,\mathbf i+(6-\cos t)\,\mathbf j\bigg)\cdot\bigg((1-\cos t)\,\mathbf i+\sin t\,\mathbf j\bigg)\,\mathrm dt

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5 0
3 years ago
Please help whoever answers this correctly I'll mark your answer brainliest​
Oksana_A [137]

Answers:

  1. Incorrect
  2. Correct
  3. Correct

==================================================

Explanation:

When applying any kind of reflections, the parallel sides will stay parallel. Check out the diagram below for an example of this.

So PQ stays parallel to RS. Also, QR stays parallel to PS.

The statement "PQ is parallel to PS" is incorrect because the two segments intersect at point P. This letter "P" is found in "PQ" and "PS" to show the common point of intersection. Parallel lines never intersect.

4 0
3 years ago
Please help thank you
matrenka [14]

Answer:

25.9 yd

Step-by-step explanation:

a^{2} + {b^{2} }  = c^{2}

(17)^{2} + {b^{2} } = (31)^{2}

289 + {b^{2} }  = 961

Subtract 289 on both sides

{b^{2} }  = 672

\sqrt{b^{2} } = \sqrt{672}

nearest tenth

b = 25.9 yd

7 0
3 years ago
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