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3 years ago

2x^2+5x-3 Show steps

Mathematics

1 answer:

lbvjy [14]3 years ago

7 0

2x^2+(6-1)x-3
2x^2+6x-x-3
2x(x+3)-1(x+3)
(2x-1)(x-1)

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A metallurgist has one alloy containing 34% copper another containing 48% copper. How many pounds of each alloy must he use to m

Zielflug [23.3K]

Answer:

<h2>36.14 pounds of 34% copper alloy and 9.86 pounds of 48% copper alloy</h2>

Step-by-step explanation:

First alloy contains 34% copper and the second alloy contains 48% alloy.

We wish to make 46 pounds of a third alloy containing 37% copper.

Let the weight of first alloy used be $x$ in pounds and the weight of second alloy used be $y$ in pounds.

Total weight = $46\text{ }pounds=x+y$ $-(i)$

Total weight of copper = $37\%\text{ of 46 pounds = }34\%\text{ of }x\text{ pounds + }48\%\text{ of }y\text{ pounds }$

$\dfrac{37\times 46}{100}=\dfrac{34x}{100}+\dfrac{48y}{100}\\\\ 34x+48y=1702$ $-(ii)$

Subtracting 34 times first equation from second equation,

$34x+48y-34x-34y=1702-34\times46\\14y=138\\y=9.857\text{ }pounds \\x=36.143\text{ }pounds$

∴ 36.14 pounds of first alloy and 9.86 pounds of second alloy were used.

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3 years ago

Joe's gas tank is 1/4 full. After he buys 6 gallons of gas, it is 5/8 full. How many gallons can Joe's tank hold?

Korolek [52]

Answer:

Amount of gas that can be hold by Joe's tank = 16 gallons.

Step-by-step explanation:

Given that Joe's gas tank is 1/4 full. After he buys 6 gallons of gas, it is 5/8 full. Now we need to find about how many gallons can Joe's tank hold.

So let's find change that happened after filling the gas.

Change = (5/8 full) - (1/4 full)

Change = (5/8 - 1/4) full

Change = (5/8 - 2/8) full

Change = (5 - 2)/8 full

Change = 3/8 full

So that means 3/8 full happens in 6 gallons

then 1 full will happen in 6/(3/8) gallons = 6*(8/3) gallons = 48/3 gallons = 16 gallons

So the amount of gas that can be hold by Joe's tank = 16 gallons.

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3 years ago

Please help with math problem?

Hoochie [10]

Answer:

KM=41.6

Step-by-step explanation:

$\frac{HJ}{IJ} =\frac{KM}{ML} \\\frac{8}{6} =\frac{KM}{31.2} \\$

Cross Multiply and Solve for KM.

$6*KM=8*31.2\\KM=\frac{8*31.2}{6} \\KM=41.6$

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1 year ago

R is the midpoint of HS, N is the midpoint of RS, and RN = 5 cm. What is the length of HS

Galina-37 [17]

Answer:

Step-by-step explanation:

RN is 1/4 of HS, and 5x4=20.

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