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gayaneshka [121]
3 years ago
6

Jada traveled 135 miles in 3 hours.Andre traveled 228 miles in 6 hours.Both jada and Andre traveled at a constant speed

Mathematics
1 answer:
Vladimir [108]3 years ago
8 0

Answer:

(a) 45 miles

(b) 38 miles

(c) Jada travels faster than Andre.

Step-by-step explanation:

(a) First we calculate the speed at which Jada travelled:

Speed = \frac{distance}{time} \\\\\\s = \frac{d}{t}

s = \frac{135}{3} \\\\\\s = 45 miles/hour

Since Jada travels at constant speed throughout the journey, we can calculate the distance traveled in 1 hour:

distance = speed * time\\\\\\distance = 45 * 1

distance = 45 miles

Jada travels 45 miles in 1 hour.

(b) We calculate the speed at which Andre travelled:

Speed = \frac{distance}{time} \\\\\\s = \frac{d}{t}

s = \frac{228}{6} \\\\\\s = 38 miles/hour

Since Andre travels at constant speed throughout the journey, we can calculate the distance traveled in 1 hour:

distance = speed * time\\\\\\distance = 38 * 1

distance = 38 miles

Andre travels 38 miles in 1 hour.

(c) Jada travels faster than Andre because he has a higher speed (45 miles/hour) than Andre ( 38 miles/hour).

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A recent study suggested that 70% of all eligible voters will vote in the next presidential election. Suppose 20 eligible voters
natita [175]

Answer:

0.0479 = 4.79% probability that fewer than 11 of them will vote

Step-by-step explanation:

For each voter, there are only two possible outcomes. Either they will vote, or they will not. The probability of a voter voting is independent of any other voter, which means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

70% of all eligible voters will vote in the next presidential election.

This means that p = 0.7

20 eligible voters were randomly selected from the population of all eligible voters.

This means that n = 20

What is the probability that fewer than 11 of them will vote?

This is:

P(X < 11) = P(X = 10) + P(X = 9) + P(X = 8) + P(X = 7) + P(X = 6) + P(X = 5) + P(X = 4) + P(X = 3) + P(X = 2) + P(X = 1) + P(X = 0)

In which

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 10) = C_{20,10}.(0.7)^{10}.(0.3)^{10} = 0.0308

P(X = 9) = C_{20,9}.(0.7)^{9}.(0.3)^{11} = 0.0120

P(X = 8) = C_{20,8}.(0.7)^{8}.(0.3)^{12} = 0.0039

P(X = 7) = C_{20,7}.(0.7)^{7}.(0.3)^{13} = 0.0010

P(X = 6) = C_{20,10}.(0.7)^{6}.(0.3)^{12} = 0.0002

P(X = 5) = C_{20,5}.(0.7)^{5}.(0.3)^{15} \approx 0

The probability of 5 or less voting is very close to 0, so they will not affect the outcome. Then

P(X < 11) = P(X = 10) + P(X = 9) + P(X = 8) + P(X = 7) + P(X = 6) + P(X = 5) + P(X = 4) + P(X = 3) + P(X = 2) + P(X = 1) + P(X = 0) = 0.0308 + 0.0120 + 0.0039 + 0.0010 + 0.0002 = 0.0479

0.0479 = 4.79% probability that fewer than 11 of them will vote

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