Answer:
2 bears in 2020.
Step-by-step explanation:
We have been given that a new bear population that begins with 150 bears in 2000 decreases at a rate of 20% per year.
We will use exponential decay formula to solve our given problem as:
, where,
y = Final quantity,
a = Initial value,
r = Decay rate in decimal form,
x = Time
Upon substituting our given values in above formula, we will get:
, where x corresponds to year 2000.
To find the population in 2020, we will substitute 
in our equation as:
Therefore, 2 bears are there predicted to be in 2020.
Since population is decreasing so population is best described as exponential decay.
Answer:
Step-by-step explanation:
This is a typical example where the Poisson distribution is a good choice to model the situation.
In this case we have an interval of time of 50 milliseconds as average time for the server to address one request and 50 requests per second.
By cross-multiplying we determine the expected value of requests every 50 milliseconds.
We know 1 second = 1,000 milliseconds
50 requests __________ 1000 milliseconds
x requests __________ 50 milliseconds
50/x = 1000/50 ===> x = 2.5
and the expected value is 2.5 requests per interval of 50 milliseconds.
According to the Poisson distribution, the probability of k events in 50 milliseconds equals
Answer:
6ft and 5ft
Step-by-step explanation:
Because 6feet times 5 feet is 30 square feet
Since they made $25 and each cost 3 divide, 25÷3=8 they sold 8 cookies
Answer: kinda confused on the function do you have a question on a piece of paper or if it is computer then take a pic of the question and upload it
Step-by-step explanation:
