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aksik [14]
3 years ago
13

equation 7(2j + 3 + 2j). use mathematical properties to create two expressions that are equivalent to the expression you created

in Question 1. Make sure you show all steps in your work.
Mathematics
1 answer:
makvit [3.9K]3 years ago
6 0

Answer:

90

Step-by-step explanation:

You might be interested in
Function is a line points (3,2), (5,8), and (8,y) what is y
SashulF [63]
Y = mx + b

(3;\ 2)\to x_1=3;\ y_1=2\\\\(5;\ 8)\to x_2=5;\ y_2=8\\\\m=\dfrac{y_2-y_1}{x_2-x_1}\to m=\dfrac{8-2}{5-3}=\dfrac{6}{2}=3

Therefore we have: y = 3x + b.

Put the coordinates of the point (3; 2) to the equation of the line:

2 = 3\cdot3+b\\2=9+b\ \ \ |-9\\b=-7

Therefore we have: y = 3x - 7

Substitute the coordinates of the point (8; y) to the equation of the line:

y = 3\cdot8-7=24-7=17

Answer: y = 17.
6 0
3 years ago
Find the volume of the cone in terms of pi. <br>405TT cm3 <br>324TT cm3 <br>72TT cm3​
Elden [556K]

Answer:

324πcm³

Step-by-step explanation:

Volume=⅓πr²h

⅓*π*9²*12

=324πcm³

3 0
3 years ago
Solve for x in the triangle. Round your answer to the nearest tenth.
Solnce55 [7]

Answer:

<h2>5 . 8</h2><h2 />

Step-by-step explanation:

Hypotenuse = 8\\Adjacent = x\\ Angle = \alpha  = 43\\\\Using ; SOHCAHTOA , \\Cos \alpha  = \frac{adj}{hyp} \\Cos 43 =\frac{x}{8} \\0.73= \frac{x}{8} \\x = 0.73*8\\x = 5.84\\x = 5.8

I hope i am correct

6 0
3 years ago
The route used by a certain motorist in commuting to work contains two intersections with traffic signals. The probability that
Mariulka [41]

Answer: a. 0.05

b. 0.40

c. 0.85

Step-by-step explanation:

Let F= Event that a certain motorist must stop at the first signal.

S =  Event that a certain motorist must stop at the second signal.

As per given,

P(F) = 0.45 , P(S) = 0.5 and P(F or S) = 0.9

a. Using general probability formula:

P(F and S) =P(F) + P(S)-  P(F or S)

= 0.45+0.5-0.9

= 0.05

∴ the probability that he must stop at both signals = 0.05

b. Required probability = P(F but (not s)) = P(F) - P(F and S)

= 0.45-0.05= 0.40

∴ the probability that he must stop at the first signal but not at the second one =0.40

c. Required probability = P(exactly one)= P(F or S) - P(F and S)

= 0.9-0.05

= 0.85

∴   the probability that he must stop at exactly one signal = 0.85

7 0
3 years ago
Solve pls brainliest
Talja [164]

Answer:

Mixed number: 5(1/10)

Improper fraction: (51/10)

Step-by-step explanation:

Hope this helps!

8 0
3 years ago
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