What is the answer to 2/3 1/8 1/12?

kati45 [8]

The answer is 6. Check photo for steps and please mark me as brainliest!

5 0

3 years ago

If P (5, 1), Q (8, 0), R (0, 4), S (0, 5) and O (0, 0) are plotted on the graph paper, then the point(s) on the x-axis are

Delvig [45]

Answer:

its D Q and O

Step-by-step explanation:

7 0

3 years ago

kinata goes for swimming lessons every 5 days while wayo goes every 6 days. if both kinata and wayo had lessons together at the

eduard

5*6=30
and 6*5=30
basically we have to take Lcm of 5 and 6=30
30th day they both will be together

4 0

2 years ago

The distribution of resistance for resistors of a certain type is known to be normal, with 10% of all resistors having a resista

baherus [9]

Answer:

The mean is 9.65 ohms and the standard deviation is 0.2742 ohms.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

10% of all resistors having a resistance exceeding 10.634 ohms

This means that when X = 10.634, Z has a pvalue of 1-0.1 = 0.9. So when X = 10.634, Z = 1.28.

$Z = \frac{X - \mu}{\sigma}$

$1.28 = \frac{10.634 - \mu}{\sigma}$

$10.634 - \mu = 1.28\sigma$

$\mu = 10.634 - 1.28\sigma$

5% having a resistance smaller than 9.7565 ohms.

This means that when X = 9.7565, Z has a pvalue of 0.05. So when X = 9.7565, Z = -1.96.

$Z = \frac{X - \mu}{\sigma}$

$-1.96 = \frac{9.7565 - \mu}{\sigma}$

$9.7565 - \mu = -1.96\sigma$

$\mu = 9.7565 + 1.96\sigma$

We also have that:

$\mu = 10.634 - 1.28\sigma$

So

$10.634 - 1.28\sigma = 9.7565 + 1.96\sigma$

$1.96\sigma + 1.28\sigma = 10.645 - 9.7565$

$3.24\sigma = 0.8885$

$\sigma = \frac{0.8885}{3.24}$

$\sigma = 0.2742$

The mean is

$\mu = 10.634 - 1.28\sigma = 10 - 1.28*0.2742 = 9.65$

The mean is 9.65 ohms and the standard deviation is 0.2742 ohms.

8 0

3 years ago

Estimate the following quantities without using a calculator. Then find a more precise result, using a calculator if necessary.

zubka84 [21]

Explanation:

a. It is so easy to double a number that no approximation is necessary.

31,000 × 200 = 3.1×10⁴ × 2×10² = 6.2×10⁶ exactly

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b. 6.2×10³ × 5.2×10⁶ ≈ 6×5×10⁹ = 3×10¹⁰ approximately

The approximation can be refined a bit by taking the ".2" into account:

6.2×10³ × 5.2×10⁶ ≈ (6×5 + .2×(6+5))×10⁹

= 32.2×10⁹ = 3.22×10¹⁰ approximately

Actual product: 3.224×10¹⁰.

For most purposes, the approximation is an adequate approximation, as it it within 10% of the actual value.

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c. 9×10⁶ -2.3×10⁴ ≈ 9×10⁶ approximately

A better approximation is to actually subtract an approximation of the smaller number:

9×10⁶ -2.3×10⁴ ≈ (9 - 0.02)×10⁶ ≈ 8.98×10⁶ approximately

The actual value uses all of the digits of the smaller number:

9×10⁶ -2.3×10⁴ ≈ (9 - 0.023)×10⁶ = 8.977×10⁶ exactly

As in part B, either approximation is adequate for most purposes, as the difference from the actual value is less than .3%.

_____

The accuracy required of an approximation, hence the work you expend improving accuracy, should depend on the need in the final application of the number. Often, approximations are used for budget or resource planning purposes where some "slop" is allowed or even expected.

They can also be used in engineering applications, where the error needs to be on the side of more safety (rather than less).

7 0

2 years ago