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andrey2020 [161]
3 years ago
5

Algebra about ages please help

Mathematics
1 answer:
valentinak56 [21]3 years ago
3 0

To solve this problem, we need to recognize that Harry's age is given as "n".  We can use this value and the given information to write expressions representing each person's age.

For Example, Jo is 2 years older than Harry and Harry's age is represented by the variable n.  This means that n (Harry's age) plus 2 would equal Jo's age.  This can be represented by the expression: n +2.

Next, we know that Kate is twice as old as Jo, and Jo's age is represented by the expression n+2.  This means that 2 times Jo's age would be equal to Kate's age, or Kate's age = 2(n+2) or 2n +4.

Therefore, your answer is that Jo's age is n + 2 and Kate's age is 2n + 4.

Hope this helps!

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3a + 3b-2c-2d

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if you draw 3hearts, 2 diamonds, and 1 spade, just replace a=3, b=2, c=0, d=1

3(3) + 3(2)-2(0)-2(1)

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Fist convert the equation to vertex form

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A track star runs two races on a certain day. The probability thathe wins the first race is 0.7, the probability that he wins th
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Answer:

a) 80% probability that he wins at least one race.

b) 30% probability that he wins exactly one race.

c) 20% probability that he wins neither race.

Step-by-step explanation:

We solve this problem building the Venn's diagram of these probabilities.

I am going to say that:

A is the probability that he wins the first race.

B is the probability that he wins the second race.

C is the probability that he does not win any of these races.

We have that:

A = a + (A \cap B)

In which a is the probability that he wins the first race but not the second and A \cap B is the probability that he wins both these races.

By the same logic, we have that:

B = b + (A \cap B)

The probability that he wins both races is 0.5.

This means that A \cap B = 0.5

The probability that he wins the second race is 0.6

This means that B = 0.6

B = b + (A \cap B)

0.6 = b + 0.5

b = 0.1

The probability that he wins the first race is 0.7.

This means that A = 0.6

A = a + (A \cap B)

0.7 = a + 0.5

a = 0.2

A) he wins at least one race.

This is

P = a + b + (A \cap B) = 0.2 + 0.1 + 0.5 = 0.8

There is an 80% probability that he wins at least one race.

B) he wins exactly one race.

This is

P = a + b = 0.2 + 0.1 = 0.3

There is a 30% probability that he wins exactly one race.

C) he wins neither race

Either he wins at least one race, or he wins neither. The sum of these probabilities is 100%.

From a), we have that there is an 80% probability that he wins at least one race.

So there is a 100-80 = 20% probability that he wins neither race.

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Step-by-step explanation: You welcome

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