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malfutka [58]
3 years ago
9

C = 7a^4+ + 5a²b2 – 3b^4 D=5a^4 + 7a²b^2 + 3b^4 C - D =

Mathematics
2 answers:
levacccp [35]3 years ago
8 0

Answer:

C-D is: \mathbf{4b^4 -2a^b^2 -6b^4}

Step-by-step explanation:

We are given:

C = 7a^4+ + 5a^2b2 - 3b^4\\D=5a^4 + 7a^2b^2 + 3b^4

We need to find C-D.

Finding C-D we actually have to subtract D from C

So, finding C-D

C-D\\= 7a^4+ + 5a^2b2 - 3b^4-(5a^4 + 7a^2b^2 + 3b^4)\\=7a^4+ + 5a^2b2 - 3b^4-5a^4-7a^2b^2-3b^4

Now, combining the like terms.

Like terms are those that have same variables and exponents.

In our case, 7a^4\: and\: 3b^4, 5a^2b^2\: and\: -7a^b^2, -3b^4\:and\:-3b^4

=7a^4 - 3b^4+5a^2b^2 -7a^b^2 -3b^4-3b^4\\=4b^4 -2a^b^2 -6b^4

So, we get C-D is: \mathbf{4b^4 -2a^b^2 -6b^4}

Gekata [30.6K]3 years ago
5 0

Answer:

2a^4 +12a

2 {a}^{4}  + 12 { a}^{2}  \\  \times  \times

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