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strojnjashka [21]
3 years ago
5

Which completely describes the polygon

Mathematics
1 answer:
Mrrafil [7]3 years ago
4 0

Answer:

NONE OF THE ABOVE!!

Step-by-step explanation:

A regular polygon is equilateral and equiangular, and also, can be inscribed into a circle. The polygon shown doesn't meet any of these conditions.

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Help and explain explain !!!!!!!!!!
tigry1 [53]

Answer:

x=-1\text{ or }x=11

Step-by-step explanation:

For a=|b|, we have two cases:

\begin{cases}a=b,\\a=-b\end{cases}

Therefore, for 18=|15-3x|, we have the following cases:

\begin{cases}18=15-3x,\\18=-(15-3x)\end{cases}

Solving, we have:

\begin{cases}18=15-3x, -3x=3, x=\boxed{-1},\\18=-(15-3x), 18=-15+3x, 33=3x, x=\boxed{11}\end{cases}.

Therefore,

\implies \boxed{x=-1\text{ or }x=11}

3 0
2 years ago
0.3(4+8)/-0.1+5/(9.2+13.2) HELP ME PLEASE!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
aleksklad [387]
0.3(4+8)/-0.1+5/(9.2+13.2)= -35.7767857143
8 0
2 years ago
Find the rate of decay of the function b(x)=4(0.006)^x<br><br> Enter your answer as a percent
yuradex [85]
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Read 2 more answers
A jewelry designer is making a pendant. The pendant will be a circular dis (center O) with a circular hold cut out of it, as sho
antoniya [11.8K]

Answer:

2884.8 millimeters squared

Step-by-step explanation:

Given:

The radius of the disc is 35 millimeters, so the area of it is:

πr^{2} = 3.14*35^{2} = 3846.5

Then, we find out the area of the circular hold cut out of the bigger one, its radius is a haft of the radius of the bigger circle = 35/2 = 17.5

πr^{2} = 3.14*17.5^{2} =961.6

=>  the area of the pendant = 3846.5  - 961.6  =2884.8 millimeters squared

6 0
3 years ago
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