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olga_2 [115]
2 years ago
9

Karina ate 1/2 of the muffins. Ulysses ate 1/4 of the muffins. Zawanna ate 1/5 of the muffins. Juan ate the rest of the muffins.

What fraction of the muffins did Juan eat?
Mathematics
1 answer:
erastovalidia [21]2 years ago
4 0

Answer:

1/20

Step-by-step explanation:

Karina ate 1/2 of the muffins. Ulysses ate 1/4 of the muffins. Zawanna ate 1/5 of the muffins. Juan ate the rest of the muffins. What fraction of the muffins did Juan eat?

Let the total number of muffins = 1

Hence:

The fraction of muffins Juan ate =

1 - (1/2 + 1/4 + 1/5)

Lowest common denominator is 20

1 - ( 10 + 5 + 4/20)

1 - 19/20

= 1/20

The Fraction of muffins Juan ate is 1/20

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How much water must be evaporated from 130 gallons of a 9% acid solution to make a 12% acid solution?
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Answer: 33 gallons

Step-by-step explanation:

We initially have 130 gallons of a 9\% acid solution and we need to change it to a 12\% acid solution, and for that it is necessary to evaporate n gallons of water.

So, this situation can be mathemtically expressed as follows:

(130)(9\%)=(130-n)(12\%)

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(130)(\frac{9}{100})=(130-n)(1\frac{12}{100})

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a)8

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Step-by-step explanation:

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A 140 kg camera is suspended by two wires over a 40 metre wide football field to get shots of the action from above. At one poin
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Answer:

Please red the answer below

Step-by-step explanation:

In order to determine the length of each cable you use the Newton second law for each component of the forces involved in the situation.

For the x component you have:

T_1cos\theta_1-T_2cos\theta_2=0           (1)

T1: tension of the first cable = 1500N

T2: tension of the second cable = 800N

θ1: angle between the horizontal and the first cable

θ2: angle between the horizontal and the first cable

For the y component you have:

T_1sin\theta_1+T_2sin\theta_2-W=0               (2)

W: weight of the camera = Mg = (140kg)(9.8m/s^2) = 1372N

You can squared both equations (1) and (2) and the sum the two equations:

T_1^2cos^2\theta_1=T_2^2cos^2\theta_2\\\\T_1^2sin^2\theta_1=T_2^2sin^2\theta_2-2WT_2sin\theta_2+W^2

Then, you sum the equations:

T_1^2(cos^2\theta_1+sin^2\theta_1)=T_2^2(sin^2\theta_2+cos^2\theta_2)-2Wsin\theta_2+W^2        (3)

Next, you use the following identity:

sin^2\theta+cos^2\theta=1

and you obtain in the equation (3):

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With this values you can calculate the value of the another angle, by using the equation (1):

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By using the cosine law you can fins a system of equation and then you can calculate the values of l1 and l2.

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