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sleet_krkn [62]
3 years ago
11

5. Write the slope-intercept form of the equation that passes through the point (-1, 2) and is perpendicular to the line y = 3/2

x + 6
O y = 3/2x + 5/2
O y = 3/2x + 4/3
O y = -2/3x + 5/2
O y = -2/3x + 4/3
Mathematics
1 answer:
kap26 [50]3 years ago
6 0

Answer:

D.  y = -2/3 x + 4/3

Step-by-step explanation:

When you have a perpendicular line, everything except the y-intercept becomes opposite. So 3/2x + 6 will become -2/3x.

To find the slope, you have to plug the coordinates into the equation so far which is y = -2/3x + b

y = -2/3x + b

2 = -2/3(-1) + b

2 = 2/3 + b

4/3 = b

So the equation is y = -2/3 x + 4/3.

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A rectangular box has a base that is 4 times as long as it is wide. The sum of the height and the girth of the box is 200 feet.
enyata [817]

Answer: V(W) = (1/3)*(*W^2*800ft - 8W^3) and the domain is 0 < W < 100ft.

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H = heigth.

We know that:

L = 4*W

And the girth of a box is equal to: G = 2*W + 2*H

then we have:

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L = 4*W

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We want to find the volume of the box, which is V = W*L*H

and we want in on terms of W.

Then, first we can replace L by 4*W (for the first equation)

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then the volume is:

V(W) = W*(4*W)*(200ft - 2*W)/3

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The domain of this is the set of W such that the volume is positive, then we must have that:

W^2*800ft > 8W^3

To find the maximum W we can see the equality (the minimum extreme is 0 < W, because the width can only be a positive number)

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