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sleet_krkn [62]
3 years ago
11

5. Write the slope-intercept form of the equation that passes through the point (-1, 2) and is perpendicular to the line y = 3/2

x + 6
O y = 3/2x + 5/2
O y = 3/2x + 4/3
O y = -2/3x + 5/2
O y = -2/3x + 4/3
Mathematics
1 answer:
kap26 [50]3 years ago
6 0

Answer:

D.  y = -2/3 x + 4/3

Step-by-step explanation:

When you have a perpendicular line, everything except the y-intercept becomes opposite. So 3/2x + 6 will become -2/3x.

To find the slope, you have to plug the coordinates into the equation so far which is y = -2/3x + b

y = -2/3x + b

2 = -2/3(-1) + b

2 = 2/3 + b

4/3 = b

So the equation is y = -2/3 x + 4/3.

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Alex_Xolod [135]

Answer:

Solving for x. Want to solve for y instead?

1 Factor out the common term 44.

4(7x+8y)=884(7x+8y)=88

2 Divide both sides by 44.

7x+8y=\frac{88}{4}7x+8y=

4

88

3 Simplify \frac{88}{4}

4

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to 2222.

7x+8y=227x+8y=22

5 0
4 years ago
If the sin 60 agrees equals the square root of three over two which statement is true
torisob [31]
Given that
\sin60^o= \frac{ \sqrt{3} }{2}

\cos 30^o =\sin(90-30)^o=\sin60^o=\frac{ \sqrt{3} }{2},

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\cos30^o\neq0,

\cos120^o\neq0

Therefore, the true statement is
\cos 30^o =\sin(90-30)^o=\sin60^o=\frac{ \sqrt{3} }{2},
because the cosine and sine are complements.
3 0
3 years ago
Solve:<br><br> A.152<br> B.176<br> C.5<br> D.27
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Answer:

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Answer:

Can you provide the chart?

Step-by-step explanation:

7 0
4 years ago
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