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Eduardwww [97]
3 years ago
9

Eva wants to make two pieces of pottery. She needs 3/5 pound of clay for one piece and 7/10 pound of clay for the other piece. S

he has 3 bags of clay that weigh 4/5 pounds each. How many bags of clay will Eva need to make both pieces of pottery? How many pounds of clay will she have left?
Mathematics
1 answer:
kow [346]3 years ago
4 0
The answer is 1.1 pounds left.
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Find a formula for the nth term of the geometric sequence. Assume the n begins with 1. a1=18, a2=9​
LUCKY_DIMON [66]

Answer:

Option E

Step-by-step explanation:

Explicit formula of a geometric sequence is,

T_n=a_1(r)^{n-1}

Here, a_1= First term

r= common ratio

n= number of terms

If, a_1=18 and a_2=9

Common ratio of the sequence r=\frac{a_2}{a_1}

r=\frac{9}{18}

r=\frac{1}{2}

By substituting these values in the formula,

T_n=18(\frac{1}{2} )^{n-1}

Therefore, Option E is the answer.

6 0
3 years ago
Lesson 6.07
Oduvanchick [21]

Answer:

A) Interval estimate for those that want to get out earlier = (35%) ± (4%) = (31%, 39%)

Interval estimate for those that want to get out later = (39%) ± (4%) = (35%, 43%)

B) The group that wants to get out of school earlier can win after all the votes are counted if their true population proportion takes on a value that is higher than the closest true population proportion (for the group that wants to get out of school later)

That is, in the (31%, 39%) and (35%, 43%) obtained in (a), a range of (35.1%, 39%) and (35%, 38.9%) show how possible that the group that wants to get out of school earlier can win after all the votes are counted.

Step-by-step explanation:

The Interval estimate for the a proportion is basically an interval of range of values where the true population proportion can be found with a certain level of confidence.

Mathematically,

Interval estimate = (Sample proportion) ± (Margin of error)

Margin of Error is the width of the confidence interval about the proportion.

a) Find the interval estimates

i) for those that want to get out earlier and

ii) those that want to get out later.

i) Sample proportion of those that want to get out earlier = 35%

Margin of Error = 4%

Interval estimate for those that want to get out earlier = (35%) ± (4%) = (31%, 39%)

ii) Sample proportion of those that want to get out later = 39%

Margin of Error = 4%

Interval estimate for those that want to get out later = (39%) ± (4%) = (35%, 43%)

b) Explain how it would be possible for the group that wants to get out of school earlier to win after all the votes are counted.

Since the interval estimates represent the range of values that the true population proportion can take on for each group that prefer a particular option, the group that wants to get out of school earlier van have their proportion take on values between 31% and 39%. If their true population takes on a value that is highest (which is very possible from the interval estimate), and the group with the highest proportion in the sample, (the group that wants to get out of school later, whose true population proportion can take between 35% and 43%) has a true population proportion that is less than that of the group that wants to get out of school earlier, then, the group that wants to get out of school earlier can win after all the votes are counted.

Hope this Helps!!!

7 0
3 years ago
Please help me with thsi
qaws [65]
Since the whole number here would be 100 all you would need to do is take 950/100 so you can take 9 whole buckets out wich is 900  so that leave you with 50 and that's half of 100 so the answer would be 9 and one half 
3 0
2 years ago
Read 2 more answers
PLEASE PLEASE help me I WILL GIVE BRAINLIEST
ale4655 [162]

1. y   1.2y  are like terms

Choice A

2.   2 + 17x-5x+9 =

   11+12x

12x+11

Choice B


3. 3(5y+6)-4

  15y+18-4

15y+14

Choice C


4.  81-27p

27(3-p)

Choice B

8 0
3 years ago
A sportswriter wants to know how strongly Albuquer-
bagirrra123 [75]

Answer:

C

Step-by-step explanation:

4 0
3 years ago
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