Write each word name as a decimal Need help with C. and H.

Write a polynomial function in standard form with zeros at −3, −1, and 1.

Annette [7]

Answer:

$f(x) = {x}^{3} + 3 {x}^{2} - x -3$

Step-by-step explanation:

The given polynomial has zeros at:

x=−3, x=−1, and x=1.

This means that:

x+3, x+1, and x-1 are all factors of this polynomial.

The factored form of this polynomial is :

$f(x) = (x + 3)(x + 1)(x - 1)$

We expand the last two factors using difference of two squares.

$f(x) = (x + 3)( {x}^{2} - 1)$

$f(x) = x ( {x}^{2} - 1) + 3( {x}^{2} - 1)$

$f(x) = {x}^{3} - x+ 3 {x}^{2} -3$

$f(x) = {x}^{3} + 3 {x}^{2} - x -3$

This is the standard form because it is now in decreasing powers of x.

8 0

3 years ago

Evaluate the expression when a = -4 and x=5. -5a +x

bonufazy [111]

Answer:

Step-by-step explanation:

5 0

2 years ago

Read 2 more answers

Slader records show that the average life expectancy of a pair of shoes is 2.2 years with astandard deviation of 1.7 years. A ma

Oksanka [162]

Answer:

For every 1000 pairs sold, the manufacturer expect to replace 239 pairs for free.

Step-by-step explanation:

Given:

Mean (μ) = 2.2, Standard deviation(S.D) (σ) = 1.7 years and x = 1 (1 year)

Let's find the Z score.

Z = $\frac{x - mean}{S.D}$

Now plug in the given values in the above formula, we get

Z = $\frac{1 - 2.2}{1.7} = -0.71$

Now we have to use the z-score table.

The z-score for 0.71 is 0.2611

Since it z is negative, so we subtract 0.2611 from 0.5000

0.5000 - 0.2611 = 0.2389

Percentage = 0.2389 × 100 = 23.89%

To find replaces for 1000 pairs, we need to multiply 23.89% by 1000

= $\frac{23.89}{100} .1000 = 238.9$

= 239

The cannot be in decimal, when we round off to the nearest whole, we get

239

3 0

3 years ago

The operation manager at a tire manufacturing company believes that the mean mileage of a tire is 30,393 miles, with a standard

Pie

Answer:

52.84% probability that the sample mean would differ from the population mean by less than 339 miles in a sample of 37 tires if the manager is correct

Step-by-step explanation:

To solve this question, we have to understand the normal probability distribution and the central limit theorem:

Normal probability distribution:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central limit theorem:

The Central Limit Theorem estabilishes that, for a random variable X, with mean $\mu$ and standard deviation $\sigma$ , a large sample size can be approximated to a normal distribution with mean $\mu$ and standard deviation $s = \frac{\sigma}{\sqrt{n}}$

In this problem, we have that:

$\mu = 30393, \sigma = 2876, n = 37, s = \frac{2876}{\sqrt{37}} = 472.81$

What is the probability that the sample mean would differ from the population mean by less than 339 miles in a sample of 37 tires if the manager is correct

This probability is the pvalue of Z when X = 30393 + 339 = 30732 subtracted by the pvalue of Z when X = 30393 - 339 = 30054. So

X = 30732

$Z = \frac{X - \mu}{\sigma}$

By the Central Limit Theorem

$Z = \frac{X - \mu}{s}$

$Z = \frac{30732 - 30393}{472.81}$

$Z = 0.72$

$Z = 0.72$ has a pvalue of 0.7642.

X = 30054

$Z = \frac{X - \mu}{s}$

$Z = \frac{30054 - 30393}{472.81}$

$Z = -0.72$

$Z = -0.72$ has a pvalue of 0.2358

0.7642 - 0.2358 = 0.5284

52.84% probability that the sample mean would differ from the population mean by less than 339 miles in a sample of 37 tires if the manager is correct

4 0

3 years ago

Go Math grade 6 standards practice workbook common core edition pages 101 & 102

notka56 [123]

Bruhhhhhhhhhhhbkfifjkgjdjcjcigcjc

3 0

3 years ago