Given a group of
n object. We want to make a selection of
k objects out of the n object. This can be done in
C(n, k) many ways, where

,
where k!=1*2*3*...(k-1)*k
Thus, we can do the selection of 3 cd's out of 5, in C(5,3) many ways,
where

Answer: 10
9514 1404 393
Answer:
x ∈ {2.07014981016}
Step-by-step explanation:
The equation can be rewritten as ...
√x = 18-8x
x = 324 -288x +64x²
64x² -289x +324 = 0
x = (289 ±√577)/128 ≈ {2.07015, 2.44548}
Since √x must be positive, we know that ...
18 -8x ≥ 0
x ≤ 18/8 = 2.25
The larger of the above solutions is extraneous, so the solution set is ...
x ∈ {(289 -√577)/128} ≈ {2.07015}
Answer:
Step-by-step explanation:
Answer:
$630 Per Month
Step-by-step explanation:
$22,500-$10,000=$12,500-$4,400=$8,100-$1,800=$6,300/10Months
=$630