The quadratic equation would be;
x2+15x-2=0
Working:
Assuming the area around the painting i.e the frame, has a uniform thickness, then;
Length of painting and frame = 8+x
Breadth of painting and frame= 7+x
The area from above step gives;
A= LxW
A= (8+x)(7+x)
On expanding, 56+8x+7x+x2
On simplifying,
56+15x+x2. This should be equal to 58.
58=x2+15x+56
Taking 58 to the other side,
x2+15x-2=0
We can use the vertex form

to find the equation of the graph. We know that a is the coefficient, and since the graph opens upwards and is slightly stretched vertically, we know that a is 1/3. On the graph, we see that the vertex of the parabola is at (0,-1). Therefore, h is 0 and k is -1.
Our vertex form equation is

Which is D
Answer:
From <u>fourth</u> month onwards, the growth rate of
is greater than that of
.
Step-by-step explanation:
Given:
The growth rates of both bank accounts are given as:

Now, as per question, we need to find the value of 'x' when the value of
. Or,

Now, we can do this by checking the values of 'x' by hit and trial method.
Let
. The inequality becomes:

Let
. The inequality becomes:

Let
. The inequality becomes:

Let
. The inequality becomes:

Therefore, the value of 'x' for which
is 4.
So, from the fourth month onwards, the balance in
becomes greater than
.
The graphical solution is shown below to support the same.
From the graph, we can conclude that after the 'x' value equals 3.4, the graph of
lies above of
. Hence,
for 

(5, 9), (5, -2)
x1 y1 x2 y2
Plug in what we know:

Subtract:

We can't divide by zero, so:
Hey can you retype the equation for 5 with the equal sign. All you can do is substitute 0 in h(t) and solve. If you don’t know how to I’ll gladly help you but plz retype the function so I know what it looks like.