Let's present the given equation first. Deciphering the given code, I think the equation is (n+1)²/n+23. Then, we want to find the maximum value of n. Suppose the complete equation is:
f(n) = (n+1)²/n+23
To find the maximum,let's apply the concepts in calculus. The maxima can be determined by setting the first derivative to zero. Therefore, we use the chain rule to differentiate the fraction. For a fraction u/v, the derivative is equal to (vdu-udv)/v².
f'(n) = [(n+23)(2)(n+1)-(n+1)²(1)]/(n+23)² = 0
[(n+23)(2n+2) - (n+1)²]/(n+23)² = 0
(2n²+2n+46n+46-n²-2n-1)/(n+23)²=0
n²+46n+45=0
n = -1, -45
There are two roots for the quadratic equation. Comparing the two, the larger one is -1. Thus, the maximum value of n is -1.
Answer:
Formula ½ab sin c
you can label them yourselves
Step-by-step explanation:
given
angle c= 53°
you have a= 4.3ft
b=3.8ft
½ab sin c
½x4.3x3.8x sin 53
=8.17xsin 53
=8.17x 0.3959
=3.2345
=3.23 to nearest hundredth
Answer:
1.alternate exterior angles
2.vertical angles
3.corresponding angles
4.alternate interior angles
5.corresponding angles
6.congruent
7. congruent
8. supplementary
9. 75
10. 56
11. 119
Please mark brainliest
Also please note I am assuming you use this as a resource to check your work and not to cheat
4.32×10^6 will be ur answer I believe or 1012 * 534 * 8 = 4323264
Answer:
it depends on how many students there are in each grade.
