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3 years ago

I NEED HELP ASAP!! 4(5)(-2)=?

1 answer:

5 0

So, in an easier way to say it
4 × 5 × -2

You would start by doing
4 × 5 = 20
Then,
20 × -2 = 40

So your answer is -40

Hope I helped ♥

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Plz help me on this quick

Studentka2010 [4]

Answer: The third one

Step-by-step explanation: We can eliminate the first one right off the bat sinc we see that -4 has two outputs. Next, the graph's equation has no slope (x=3) so the input is all the same. Thirdly, the table shows a relationship between x and y and the numbers don't have a pattern that shows more than one output or input for a number. The fourth option are simply coordinates, it doesn't particularly tell us that all the coordinates are related to each other.

7 0

2 years ago

PLEASE help

astraxan [27]

Answer:

The percentage of people should be seen by the doctor between 13 and

17 minutes is 68% ⇒ 2nd term

Step-by-step explanation:

* Lets explain how to solve the problem

- Wait times at a doctor's office are typically 15 minutes, with a standard

deviation of 2 minutes

- We want to find the percentage of people should be seen by the

doctor between 13 and 17 minutes

* To find the percentage we will find z-score

∵ The rule the z-score is z = (x - μ)/σ , where

# x is the score

# μ is the mean

# σ is the standard deviation

∵ The mean is 15 minutes and standard deviation is 2 minutes

∴ μ = 15 , σ = 2

∵ The people should be seen by the doctor between 13 and

17 minutes

∵ x = 13 and 17

∴ z = $\frac{13-15}{2}=\frac{-2}{2}=-1$

∴ z = $\frac{17-15}{2}=\frac{2}{2}=1$

- Lets use the standard normal distribution table

∵ P(z > -1) = 0.15866

∵ P(z < 1) = 0.84134

∴ P(-1 < z < 1) = 0.84134 - 0.15866 = 0.68268 ≅ 0.68

∵ P(13 < x < 17) = P(-1 < z < 1)

∴ P(13 < x < 17) = 0.68 × 100% = 68%

* The percentage of people should be seen by the doctor between

13 and 17 minutes is 68%

6 0

2 years ago

Which set of numbers correctly shows all of the factors of 28? 1, 2, 4, 7, 14, 28 1, 2, 7, 14, 28 0, 1, 7, 14, 28 1, 2, 4, 7, 8,

slega [8]

Answer:

1, 2, 4, 7, 14, 28

Step-by-step explanation:

Factors of 28 are the numbers that divide into 28 evenly.

1, 2, 4, 7, 14, 28

3 0

2 years ago

Read 2 more answers

Please help me ASAP

ANTONII [103]

Answer:

Step-by-step explanation:

24 foot

8 0

2 years ago

The U.S. Census Bureau conducts annual surveys to obtain information on the percentage of the voting-age population that is regi

yan [13]

Answer:

We conclude that the percentage of employed workers who have registered to vote exceeds the percentage of unemployed workers who have registered to vote.

Step-by-step explanation:

We are given that 513 employed persons and 604 unemployed persons are independently and randomly selected, and that 287 of the employed persons and 280 of the unemployed persons have registered to vote.

Let $p_1$ = percentage of employed workers who have registered to vote.

$p_2$ = percentage of unemployed workers who have registered to vote.

So, Null Hypothesis, $H_0$ : $p_1\leq p_2$ {means that the percentage of employed workers who have registered to vote does not exceeds the percentage of unemployed workers who have registered to vote}

Alternate Hypothesis, $H_A$ : $p_1>p_2$ {means that the percentage of employed workers who have registered to vote exceeds the percentage of unemployed workers who have registered to vote}

The test statistics that would be used here Two-sample z test for proportions;

T.S. = $\frac{(\hat p_1-\hat p_2)-(p_1-p_2)}{\sqrt{\frac{\hat p_1(1-\hat p_1)}{n_1}+\frac{\hat p_2(1-\hat p_2)}{n_2} } }$ ~ N(0,1)

where, $\hat p_1$ = sample proportion of employed workers who have registered to vote = $\frac{287}{513}$ = 0.56

$\hat p_2$ = sample proportion of unemployed workers who have registered to vote = $\frac{280}{604}$ = 0.46

$n_1$ = sample of employed persons = 513

$n_2$ = sample of unemployed persons = 604

So, the test statistics = $\frac{(0.56-0.46)-(0)}{\sqrt{\frac{0.56(1-0.56)}{513}+\frac{0.46(1-0.46)}{604} } }$

= 3.349

The value of z test statistics is 3.349.

Now, at 0.05 significance level the z table gives critical value of 1.645 for right-tailed test.

Since our test statistic is more than the critical value of z as 3.349 > 1.645, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which we reject our null hypothesis.

Therefore, we conclude that the percentage of employed workers who have registered to vote exceeds the percentage of unemployed workers who have registered to vote.

5 0

2 years ago