All categories

3 years ago

Two consecutive EVEN numbers have a sum of 30. What are the numbers?

Mathematics

1 answer:

mel-nik [20]3 years ago

3 0

Answer:

14 and 16

Step-by-step explanation:

Consecutive even numbers are even numbers that follow each other from smallest to biggest for example 2,4,6,8 are consecutive even numbers. So the consecutive even numbers that have a sum of 30 are 14 and 16 (14+16=30).

HOPE IT HELPED

You might be interested in

Answer Please???? Finn is baking cakes for a party. The number of cups of sugar Finn needs is proportional to the number of cake

Natali [406]

Answer:

Hello there!

The answer to your question is :

<em>C: Finn needs 6 cups of sugar for 4 cakes.</em>

<em>D: Finn needs 1 1/2 cups of sugar for 1 cak</em>e.

Step-by-step explanation:

The graph clearly shows ( sides cups of sugar) (bottom number of cakes)

For sugar you need 6 cups to make 4 cakes

For sugar on the second question you need 1 1/2 cups of sugar to make 1 cake

Multiply 1 1/2 times 6 then divide and your answer is 4. That's 4 cakes out of 6 cups of sugar out of the original cups of sugar ( 1 1/2)

This is the confirmed answer I took the quiz and got 100%

Hopes this helps you!

~Darlington

5 0

3 years ago

2 over 8 divided by 1 over 2 =

Illusion [34]

Answer: 1 over 2 (1/2)

Simplify 2 over 8 to get 1 over 4. Now you have 1 over 4 divided by 1 over 2. Whenever you divide with fractions you flip the fraction and multiply . So it becomes 1 over 4 multiplied by 2 over 1.

2/8 (divided by) 1/2
1/4 (divided by) 1/2
1/4 x 2/1
= 1/2

7 0

3 years ago

A TV sells for $107. However, this weekend it is on sale for 84.53. What is the percent discount? The discount is

PSYCHO15rus [73]

Answer:

21% off

Step-by-step explanation:

Idk work backwards. Google numbers until it works.

20% off 107.00= 85.6

21% off 107.00= 84.53 * Yay. Answer.

22% off 107.00= 83.46

4 0

3 years ago

How many bottles can you drink?

jeka57 [31]

Step-by-step explanation:

You have 120 bottles of Cola and 120 bottles of Sprite.

You can exchange 3 empty Cola bottles for a new bottle of Sprite.

You can exchange 4 empty Sprite bottles for a new bottle of Cola.

You can borrow empty bottles, but must return them in the end.

What is the maximal number of bottles of drink that you can drink? Prove the optimality of your result.

As this is a puzzle, please give short and clever answers rather than tedious bruteforce calculations.

6 0

2 years ago

A filtration process removes a random proportion of particulates in water to which it is applied. Suppose that a sample of water

Doss [256]

Answer:

$E(Y)=\frac{1}{25}$

Step-by-step explanation:

Let's start defining the random variables for this exercise :

$X_{1}:$ '' The proportion of the particulates that are removed by the first pass ''

$X_{2}:$ '' The proportion of what remains after the first pass that is removed by the second pass ''

$Y:$ '' The proportion of the original particulates that remain in the sample after two passes ''

We know the relation between the random variables :

$Y=(1-X_{1})(1-X_{2})$

We also assume that $X_{1}$ and $X_{2}$ are independent random variables with common pdf.

The probability density function for both variables is $f(x)=4x^{3}$ for $0$ and $f(x)=0$ otherwise.

The first step to solve this exercise is to find the expected value for $X_{1}$ and $X_{2}$ .

Because the variables have the same pdf we write :

$E(X_{1})= E(X_{2})=E(X)$

Using the pdf to calculate the expected value we write :

$E(X)=\int\limits^a_b {xf(x)} \, dx$

Where $a=$ ∞ and $b=$ - ∞ (because we integrate in the whole range of the random variable). In this case, we will integrate between $0$ and $1$ ⇒

Using the pdf we calculate the expected value :

$E(X)=\int\limits^1_0 {x4x^{3}} \, dx=\int\limits^1_0 {4x^{4}} \, dx=\frac{4}{5}$

⇒ $E(X)=E(X_{1})=E(X_{2})=\frac{4}{5}$

Now we need to use some expected value properties in the expression of $Y$ ⇒

$Y=(1-X_{1})(1-X_{2})$ ⇒

$Y=1-X_{2}-X_{1}+X_{1}X_{2}$

Applying the expected value properties (linearity and expected value of a constant) ⇒

$E(Y)=E(1)-E(X_{2})-E(X_{1})+E(X_{1}X_{2})$

Using that $X_{1}$ and $X_{2}$ have the same expected value $E(X)$ and given that $X_{1}$ and $X_{2}$ are independent random variables we can write $E(X_{1}X_{2})=E(X_{1})E(X_{2})$ ⇒

$E(Y)=E(1)-E(X)-E(X)+E(X_{1})E(X_{2})$ ⇒

$E(Y)=E(1)-2E(X)+[E(X)]^{2}$

Using the value of $E(X)$ calculated :

$E(Y)=1-2(\frac{4}{5})+(\frac{4}{5})^{2}=\frac{1}{25}$

$E(Y)=\frac{1}{25}$

We find that the expected value of the variable $Y$ is $E(Y)=\frac{1}{25}$

3 0

3 years ago